Answer:
pretty sure its -2,3 :)
Step-by-step explanation:
Answer:
the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%
Step-by-step explanation:
Martha = widow's peak + attached earlobes.
Martha's dad = straight hairline + unattached earlobes.
Martha husband =straight hairline+ widow's peak + attached earlobes
what is the probability that Martha child will have a widow's peak + attached earlobes?
since,
Martha + Martha husband =straight hairline+ widow's peak + attached earlobes
the probability of the child having widow peak is 2/3 = 0.6667
the probability of the child having attached earlobes is 2/3 = 0.66667
the probability of having both = 0.6667*0.66667 = 0.4445
5x^2-8x+5=0
ax^2+bx+c=0; a=5, b=-8, c=5
Quadratic Formula:
x=[-b+-sqrt(b^2-4ac)]/(2a)
x=[-(-8)+-sqrt( (-8)^2-4(5)(5) )] / [(2)(5) ]
x=[ 8+-sqrt(64-100)] / 10
x=[ 8+-sqrt(-36)] / 10
x=[8+-sqrt( (36)*(-1)) ] /10
x=[8+-sqrt(36)*sqrt(-1)] / 10
x=(8+-6i) / 10
x=(8/2+-6i/2) / (10/2)
x=(4+-3i)/5
x1=(4-3i)/5
x2=(4+3i)/5
Answers:
x=(4-3i)/5 , x=(4+3i)/5