The number of people which gets 1/6 of the pizza as required for lunch the next day is; 4 persons.
<h3>What is the number of people who get 1/6 of the pizza for lunch?</h3>
It follows from the task content that only 4/6 of the pizza is left and each individual needs 1/6 of the pizza for lunch.
On this note, the 4/6 fraction of pizza left mean: 4 × 1/6.
Therefore, only four persons get lunch.
Read more on fractions;
brainly.com/question/17220365
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Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
Answer and Step-by-step explanation:
To solve, we would multiply by the reciprocal of the portion Jada has read, and multiply that number to 75.
The reciprocal means the the value, but flipped, so 
will become 
.
Now we do 75 times /
So, there are 125 total pages in the book.
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
Answer:
Step-by-step explanation:
(a+b)^2=a^(2)+2ab+b^(2)
(a-b)^2=a^(2)-2ab+b^(2)
13)
(x+2)^(2)-(x-1)^2
x^(2)+4x+4-(x^(2)-2x+1)
x^(2)+4x+4-x^(2)+2x-1
6x+3
15)
(x+5)^(2)-(x+1)^2
x^(2)+10x+25-(x^(2)+2x+1)
x^(2)+10x+25-x^(2)-2x-1
8x+24
