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son4ous [18]
2 years ago
10

Boht agyi yaadehmm:)​

Mathematics
2 answers:
topjm [15]2 years ago
4 0

Answer:

is this a different language?

rodikova [14]2 years ago
3 0
I don’t know what it says but hey! :)
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How to solve 3/2 = 9/10k (in fraction form). Please show work
antoniya [11.8K]
3/2 and 9/10. Look at the denominators. 2 times what number equals 10. That number would be 5. So if you multiply the first fractions denominator by 5 you get 10. Do the same to the top. you get a new fracrion which is 15/10. Add normally. 15/10 + 9/10 = 24/10. In lowest terms it is 2 2/5 (2 wholes and 2 out of 5)
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What number represents the same amount as 2 hundreds +12 tens +6 ones?
Svetradugi [14.3K]
The answer is 326. this is simple.
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Write Y+2=1/3x in standard form
solong [7]

The standard form of a line is in the form

Ax + By = C

A, B and C are integers, and A is positive. Let's start with multiplying the whole equation by 3 to get rid of denominators:

3y+6=x

Subtract 3y from both sides:

6=x-3y

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x-3y=6

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3 years ago
PLEASE HELP! WILL MARK BRAINLIEST!
Serga [27]

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its answer 4. or D.

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At an effective annual interest rate of i > 0, each of the following two sets of payments has present value K: (i) A payment
IgorLugansk [536]

Answer:

The present value of K is, K=251.35

Step-by-step explanation:

Hi

First of all, we need to construct an equation system, so

(1)K=\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}

(2)K=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}

Then we equalize both of them so we can find i

(3)\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}

To solve it we can multiply (3)*(1+i)^{4} to obtain (1+i)^{4}*(\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}), then we have 225(1+i)^{2}+225=169(1+i)^{3}+169(1+i)^{2}.

This leads to a third-grade polynomial 169i^{3}+451i^{2}+395i-112=0, after computing this expression, we find only one real root i=0.2224.

Finally, we replace it in (1) or (2), let's do it in (1) K=\frac{169}{(1+0.2224)} +\frac{169}{(1+0.2224)^{2}}\\\\K=251.35

8 0
3 years ago
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