The front part of a tent had the dimensions shown in a diagram.What is the area of this part of the tent

Mathematics

2 answers:

attashe74 [19]3 years ago

3 0

The area of this of the tent is 20

Y_Kistochka [10]3 years ago

3 0

The area of a tent is 20

BECAUSE...

8x5=40 and 40/2 is 20 sooo the answer is 20

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An account earns simple interest. $1800 at 6.5% for 30 months

Vikentia [17]

A = P(1 + rt)

Where:

A = Total Accrued Amount (principal + interest)
P = Principal AmountI = Interest Amount
r = Rate of Interest per year in decimal;
r = R/100
R = Rate of Interest per year as a percent;
R = r * 100
t = Time Period involved in months or years

Calculation:

First, converting R percent to r a decimal
r = R/100 = 6.5%/100 = 0.065 per year,
putting time into years for simplicity,
30 months ÷ 12 months/year = 2.5 years,
then, solving our equation

A = 1800(1 + (0.065 × 2.5)) = 2092.5 
A = $ 2,092.50

The total amount accrued, principal plus interest,
from simple interest on a principal of $ 1,800.00
at a rate of 6.5% per year
for 2.5 years (30 months) is $ 2,092.50.

5 0

4 years ago

HELP ASAP!!!!! SOMEONE HELP ME?!?!

Kitty [74]

Answer:

The first step when factoring any polynomial is to factor out the GCF. The GCF is the greatest common factor for all the terms of the polynomial. By factoring out the GCF first, the coefficients and constant term of the polynomial will be reduced.

4 0

3 years ago

Read 2 more answers

One of our brainliest, Konrad509, made this:

Reil [10]

$\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x$

A=10, B=11, C=12, etc.

$\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2$

$121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0$

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that $x\in\mathbb{N}$ . Moreover we can deduce that $x\geq19$ since there is $J$ and $J=19$ .