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3 years ago

Determine slope of line passing through points (1, 5) and (-5, -4)

Mathematics

1 answer:

makvit [3.9K]3 years ago

3 0

Answer:

1/6

Step-by-step explanation:

determine the difference between both of the x and y points. Ex: (x1, y1) (x2, y2) x2-x1= x3 and y2-y1= y3 so the slope would be y3/x3

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6.796 rounded to the nearest hundredth

vladimir1956 [14]

Answer: 6.80

Hope it helps!

7 0

3 years ago

Read 2 more answers

Stephen had 24 miniature cars. he gave 4 cars to his brother.then he divided 4 equally among his friends .write an expression to

Svetlanka [38]

Total number of cars with Stephen = 24

Stephen gave 4 cars to his brother,

24-4 = 20 cars are left with Stephen.

Then, Stephen divided 4 equally among his friends.

That means Stephen divided 4 cars among the friends.

So, $\frac{24-4}{5} = 4$

So, Stephen divided 4 miniature cars among 5 friends.

The expression $\frac{24-4}{5} = 4$ denotes the words given in the above context.

6 0

3 years ago

What is cube root of 108

Sonbull [250]

I believe.... $\sqrt[3]{108} = 4.762203$ .....hope it helps...:)

4 0

4 years ago

F(X)=-2x-3<br> g(X)=3X+1<br> find (fxg)(X)

Goshia [24]

Answer:

6x² - 7x - 3

Step-by-step explanation:

(f × g)(x) = f(x) × g(x), that is

(2x - 3)(3x + 1)

Each term in the second factor is multiplied by each term in the first factor, that is

2x(3x + 1) - 3(3x + 1) ← distribute both parenthesis

= 6x² + 2x - 9x - 3 ← collect like terms

= 6x² - 7x - 3

4 0

4 years ago

Suppose that three computer boards in a production run of forty are defective. A sample of five is to be selected to be checked

IgorC [24]

Answer:

(a) 658,008 different samples can be chosen.

(b) 222,111 samples will contain at least one defective board.

(c) The probability that a randomly chosen sample of five contains at least one defective board is 0.34.

Step-by-step explanation:

We are given that three computer boards in a production run of forty are defective. A sample of five is to be selected to be checked for defects.

(a) To find how many different samples can be chosen, we will use a combination formula here because the order of selecting a sample of 5 from the production run of 40 doesn't matter.

Here, n = total sample = 40 and r = selected sample = 5

So, the combination formula is; $^{n}C_r= \frac{n!}{r! \times (n-r)!}$

$^{40}C_5= \frac{40!}{5! \times (40-5)!}$

$^{40}C_5= \frac{40!}{5! \times 35!}$

$^{40}C_5$ = 658,008 ways

So, 658,008 different samples can be chosen.

(b) To find how many samples will contain at least one defective board, we will first find how many samples will contain no or 0 defective board.

For this also, we will use a combination where n = 40 - 3 = 37 non-defective computer board and a sample of r = 5 computer boards.

So, $^{n}C_r= \frac{n!}{r! \times (n-r)!}$

$^{37}C_5= \frac{37!}{5! \times (37-5)!}$

$^{37}C_5= \frac{37!}{5! \times 32!}$

$^{37}C_5$ = 435,897 ways

This means that 435,897 of the 658,008 samples will contain no defective board.

Now, the samples that will contain at least one defective board = Total samples - Samples that contain no defective board

= 658,008- 435, 897

= 222,111

(c) The probability that a randomly chosen sample of five contains at least one defective board is given by;

Required Probability = $\frac{222,111}{658,008}$

= 0.34 or 34%

3 0

4 years ago