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yarga [219]
3 years ago
15

What is cube root of 108

Mathematics
1 answer:
Sonbull [250]3 years ago
4 0
I believe....\sqrt[3]{108} = 4.762203.....hope it helps...:)
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A survey is targeted at 12 year old children. Which questions are appropriate for the population? Choose all that apply.
zubka84 [21]

Answer:

options number four is correct because they are children and they can able to identify the book.

3 0
3 years ago
Please help me I need a lot of help :(
Anna35 [415]
(3 4/7 - 3/5) x 2/3 = 208/105

3/2 x (3 4/7 - 3/5) = 156/35

That is what your two problems are when simplified.
From there on you can tell what is greater then another.
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There are 5 Germans and 5 Italians in an English class. If a group of 3 is going to be created, what is the probability that eve
MakcuM [25]

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Step-by-step explanation:

4 0
3 years ago
Make a number line and show all values of x. x≤2 and x< -5
Roman55 [17]

Answer:

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Step-by-step explanation:

3 0
2 years ago
I NEED HELP!! THIS MY FINAL!
barxatty [35]

Answer:

13.5

18.1

72.2

12.8

6,2

66.1

49.1

14

31.8

Step-by-step explanation:

In solving this question, remember the annotation SOHCAHTOA

1. We are given the value of the hypotenuse and we are to determine the value of the adjacent side. COS would be used to determine this value

Cos 26 = Adjacent / hypotenuse

cos 26 = x / 15

x / 15 =0.8988

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2. We are given the value of the hypotenuse and we are to determine the value of the opposite side. SIN would be used to determine this value

Sin = opposite / hypotenuse

sin 49 = x / 24

0.7547 = x / 24

x = 0.7547 x 24

x = 18.1

3. We are given the value of the opposite side and we are to determine the value of the adjacent side. TAN would be used to determine this value

Tan = opposite / adjacent

tan 14 = 18 /x

18 / 0.2493 = 72.2

4.  We are given the value of the adjacent and we are to determine the value of the hypotenuse side. COS would be used to determine this value

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0.3907 = 5/x

x =5/  0.3907 = 12.8

to determine the missing angle

7. tan^-1 = opposite / adjacent

8. cos^-1 = adjacent / hypotenuse

9 = sin^-1 = opposite / hyotensue

4 0
3 years ago
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