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ahrayia [7]
3 years ago
7

A town has a population of 2093 people at time t=0.The population increases by 42 people a year. Enter a formula for the populat

ion, P, of the town as a function of year t.
Mathematics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

P(t) = 2093e^(42t).

Step-by-step explanation:

The population of this town can be modeled by the following differential equation

dP/dt = Pr

where r is the growth rate in people a year.

We can solve this differential equation by the separation of variables method.

dP/P = rdt

Integrating both sides, we have:

ln P = rt + P0

where P0 is the initial population

To isolate P, we do this:

e^(ln P) = e^(rt + P0)

P(t) = P0e^(rt).

We have that the population increases by 42 people a year, so r = 42. We also have that the population at time t = 0 is 2093 people, so P0 = 2093.

So the  formula for the population, P, of the town as a function of year t is P(t) = 2093e^(42t).

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For some reason, your teacher wants P to be the third letter as s/he mentioned MNP and NMP. But again, the order doesn't matter.

3 0
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Determine the proportion of months where memberships sold decreases,

increases and remained the same.

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Let e f (x) = x2 – 2x - 4 What is the average rate of change for the quadratic function from X = -1 tox to x = 42 Enter your ans
sammy [17]

Answer:

The average rate of change of the given function

A(x) =  1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function f(x) = x² - 2x -4

And given that x = a = -1 and  x=b = 4

The average rate of change of the given function

A(x) = \frac{f(b)-f(a)}{b-a}

<u><em>Step(ii):-</em></u>

f(x) = x² - 2x -4

f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1

f(4) = 4² -2(4) -4 = 16 -12 = 4

The average rate of change of the given function

A(x) = \frac{f(b)-f(a)}{b-a}

A(x) = \frac{4-(-1)}{4-(-1)} = \frac{5}{5} = 1

<u><em>final answer:-</em></u>

The average rate of change of the given function

A(x) =  1

5 0
3 years ago
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saul85 [17]
<h3>Answer:</h3>

It depends:

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<h3>Explanation:</h3>

Louise needs to end up a total of 5 times 4 away from zero.

If she starts at 4, which is 1 times 4, then she needs to jump 4 more times, to 2, 3, 4, 5 times 4.

If she starts at 0, then she needs to jump 5 times to 1, 2, 3, 4, 5 times 4. (The values at the end of each jump will be {4, 8, 12, 16, 20}.)

4 0
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