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katen-ka-za [31]
3 years ago
11

What is the slope of the line 6x – 2y – 14 = 0?

Mathematics
1 answer:
fredd [130]3 years ago
8 0

Answer:

3

Step-by-step explanation:

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Help asap plz ill give a gold medal. the label on cars antifreeze claims to protect the car between -30celsius and 130celsius. t
irga5000 [103]
The inequality would start out looking like this:
-30\ \textless \  \frac{5}{9} (F-32)\ \textless \ 130
Now it's just a matter of solving the inequalities simultaneously. Get rid of the fraction by multiplying everything by 9:
-270\ \textless \ 5(F-32)\ \textless \ 1170
Then distribute the 5 into the parenthesis:
-270\ \textless \ 5F-160\ \textless \ 1170
Now add 160 everywhere:
-110\ \textless \ 5F\ \textless \ 1330
and finally divide everything by 5:
-22<F<266


4 0
3 years ago
At the yard sale,3\4 of items for sale were toys and 5\6 of the items for sale were books Were there more toys of books for sale
Vesnalui [34]

Answer:

No, the books had more sales by 5/6 being bigger (Greater Than) than 3/4.

5 0
3 years ago
Greg runs 3 miles in 28 minutes. At the same rate, how many miles would he run in 42 minutes?
Paladinen [302]

Answer:

4.5

 miles

Step-by-step explanation:

Well, he runs

3

miles in

28

minutes. Also, see that

42

=

28

⋅

1.5

.

So, his journey would just be running

1.5

times, with each time running

28

minutes.

So, he runs a total of

1.5

⋅

3

=

4.5

miles

7 0
3 years ago
Read 2 more answers
What equation is graphed in this equation?
jenyasd209 [6]
Y-2=-3/2(x-2)
first of all, the slope of the line is -3/2, and there's only one equation that has that as a choice for the slope. Then you can take the x and y coordinates given in that equation you want to check and see if the line goes through that point. from the equation, (point-slope form y-y=m(x-x)) I know that the line should pass through point (2, -2), and looking at the graph, that is correct.
7 0
3 years ago
What is the solution of the equation x^2 + 6x + 6 = 0?
ICE Princess25 [194]
I hope it will help you.

6 0
3 years ago
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