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balu736 [363]
3 years ago
11

Solve this inequality: j/4 – 8 < 4. A. j < –48 B. j < 48 C. j > –12 D. j < 12

Mathematics
2 answers:
postnew [5]3 years ago
4 0
J/4 - 8 < 4

j/4 < 4 + 8
j4 < 12
j < 12 X 4
j < 48
Kruka [31]3 years ago
3 0
\frac{j}{4} - 8 \ \textless \  4 \\ \\  \frac{j}{4} \ \textless \  4 + 8 \\ \\  \frac{j}{4} \ \textless \  12 \\ \\ j \ \textless \  12 \times 4 \\ \\ j \ \textless \  48 \\ \\

The final result is: j < 48.
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5 0
3 years ago
Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
2 years ago
Which equivalent fractions can you use to find the difference of 5 and 3/13 and 1 and 4/9 ?
lbvjy [14]
5 3/13 = 68/13
1 4/9 = 13/9
7 0
3 years ago
What is the value of r2s for r=10 and ​s=2?
mezya [45]

Hey there!

<h2>10(2)(2) </h2><h2>10(2) = 20</h2><h2>20(2) = 40</h2><h2>Thus, your answer is: 40</h2>

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst

3 0
2 years ago
One side of a rectangle is 3 m more than the other. If the perimeter of the rectangle is 30 m, what are its dimensions? *
uranmaximum [27]

Answer:

the length— 6

width— is 9

Step-by-step explanation:

you said One side— 3m MORE

so we will consider the length Number as X

we will consider width As three plus X

- You want to know the Perimeter. So we have to

add.

— so the expression is 3+3+x+x+x+x = 30

it is then simplified to 6+4x= 30

then we should be able to find out the X  which is 6

when we substitute the values with dimensions, you will get

your final Answer

I hope This Helped!

6 0
3 years ago
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