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balu736 [363]
3 years ago
11

Solve this inequality: j/4 – 8 < 4. A. j < –48 B. j < 48 C. j > –12 D. j < 12

Mathematics
2 answers:
postnew [5]3 years ago
4 0
J/4 - 8 < 4

j/4 < 4 + 8
j4 < 12
j < 12 X 4
j < 48
Kruka [31]3 years ago
3 0
\frac{j}{4} - 8 \ \textless \  4 \\ \\  \frac{j}{4} \ \textless \  4 + 8 \\ \\  \frac{j}{4} \ \textless \  12 \\ \\ j \ \textless \  12 \times 4 \\ \\ j \ \textless \  48 \\ \\

The final result is: j < 48.
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3 years ago
enelope determined the solutions of the quadratic function by completing the square. f(x) = 4x2 + 8x + 1 –1 = 4x2 + 8x –1 = 4(x2
Marat540 [252]
The correct question is
<span>Penelope determined the solutions of the quadratic function by completing the square.
f(x) = 4x² + 8x + 1
–1 = 4x² + 8x
–1 = 4(x² + 2x)
–1 + 1 = 4(x² + 2x + 1)
0 = 4(x + 2)²
0 = (x + 2)²
0 = x + 2
–2 = x
What error did Penelope make in her work?

we have that
</span>f(x) = 4x² + 8x + 1
to find the solutions of the quadratic function
let
f(x)=0
 4x² + 8x + 1=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

 (4x² + 8x)=-1

Factor the leading coefficient 

 4*(x² + 2x)=-1

Complete the square Remember to balance the equation by adding the same constants to each side.

 4*(x² + 2x+1)=-1+4 --------> ( added 4 to both sides)

Rewrite as perfect squares

4*(x+1)²=3

(x+1)²=3/4--------> (+/-)[x+1]=√3/2

(+)[x+1]=√3/2---> x1=(√3/2)-1----> x1=(√3-2)/2

(-)[x+1]=√3/2----> x2=(-2-√3)/2

therefore

the answer is

<span>Penelope should have added 4 to both sides instead of adding 1.</span>
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