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almond37 [142]
3 years ago
9

Ryan is making a fruit drink. The directions say to mix 5 cups of water with 2 scoops of powdered fruit mix. How many cups of wa

ter should he use with 9 scoops of fruit mix?
Rate needed:

Ryan is making a fruit drink. The directions say to mix 5 cups of water with 2 scoops of powdered fruit mix. How many cups of water should he use with 9 scoops of fruit mix?

Rate needed:
How many cups water /

How many scoops mix.



Ryan should use
how many cups of water for each scoop of mix.
Mathematics
1 answer:
Nuetrik [128]3 years ago
6 0
22.5 cups of water for 9 scoops
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Answer:

60/5 is equal to 12. so 12 x 2= 24, and 5 x 12=60, so 24/60, or just 24

Step-by-step explanation:

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A manager hires labour and rents capital equipment in a very competitive market. Currently the wage rate is GH¢2 per hour and ca
Veseljchak [2.6K]

Solution :

It is given that the manager hires a labor and he rents the capital equipment \text{in a very competitive market}.

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Therefore, the answer is

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3 years ago
Find an expression for the nth term -3 , 2 , 7, 12​
slavikrds [6]

Answer:

5n-8

Step-by-step explanation:

Because this is an arithmetic progression, there is simply an addend that is being added to every number. Because that is 5, the expression, for now, would be 5n. However, the progression does not start at 0, so we will have to subtract 3, and then it would be 5n - 3. We're still not at the answer; this is because the first term starts at 1, not 0. We will have to account for that, so subtract the coefficient, or 5, from the whole expression. That would be 5n - 8, and that would be the answer.

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3 years ago
What is the solution? 2/3(x-7)= -2
koban [17]

Answer:

x =4

Step-by-step explanation:

2/3(x-7)= -2

Multiply each side by 3/2 to clear the fractions

3/2 * 2/3(x-7)= -2 *3/2

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3 0
3 years ago
Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
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