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saw5 [17]
3 years ago
13

A. A 5in radius ball is in a

Mathematics
1 answer:
abruzzese [7]3 years ago
5 0

Answer:

52.33%

Step-by-step explanation:

Since, all six sides of the box are touching the ball.

So, all the three dimensions of the box are equal.

Hence, it is a cubical box.

Side length of the box (l)

= diameter of the ball

= 2*radius of the ball

= 2*5

= 10 In.

V_{ball} = \frac{4}{3} \pi r^3

V_{ball} = \frac{4}{3} \times 3.14(5)^3

V_{ball} = \frac{4}{3} \times 3.14\times 125

V_{ball} = \frac{1,570}{3}\: In^3

V_{box} =l^3

V_{box} =(10)^3

V_{box} =1000\: In^3

Percentage of the space in the box occupied by the ball

= \frac{V_{ball}}{V_{box} } \times 100

= \frac{\frac{1,570}{3}}{1000} \times 100

= \frac{1570}{3000} \times 100

= \frac{157}{3}

= 52.33\%

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