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3 years ago

The growth of a bacteria each hour is given by the function

Mathematics

2 answers:

IgorC [24]3 years ago

8 0

I believe the answer is 286 since the equation is 250(1.07) t

this tells me that 250= original size and 1.07= growth of the bacteria and t for time or hour in this case

250x(1.07) 2

267.5x(1.07)

286.225 = 286

marysya [2.9K]3 years ago

5 0

500 I guess it’s not right

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Nate spent $28 on 2 dvds.at this rate how much would 5 dvds cost him

Anuta_ua [19.1K]

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3 years ago

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iVinArrow [24]

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3 years ago

rohana wants to find the volume of a sphere that has a radius of 10 feet. which equation can she use to solve for this value in

Vitek1552 [10]

The equation that can be used to determine the volume of the sphere is 4/3π10³

<h3>What is the volume of the sphere?</h3>

A sphere is a three-dimensional object in which points from its center to its circumference is equidistant.

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Where:

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To learn more about the volume of a sphere, please check: brainly.com/question/13705125

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2 years ago

Choose the graph of the function y = -tan 4x.

dalvyx [7]

Step-by-step explanation:

I have attached the graph of the question. So this is the graph of the question and i also attached the solved question screen shot.

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3 years ago

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

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3 years ago