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Bas_tet [7]
3 years ago
15

Is the GCF (greatest common factor) of a pair of numbers ever equal to one of the numbers? Explain why or why not.

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

Yes, that is possible because whenever one number is a factor of the other one, it's their greatest common factor. Here are some examples.

2 and 200

10 and 100

13 and 52

one thousand and one million

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Whats 1/3 of 2/4
lara31 [8.8K]

Answer:

0.16666666666 or 16666666666/100000000000

Step-by-step explanation:

8 0
2 years ago
What is the graph of the function y = |x| + 2? How is this graph different from the parent function?
Molodets [167]

Answer:

1

Step-by-step explanation:

5 0
3 years ago
If you place a 26-foot ladder against the top of a 10-foot building, how many feet will the bottom of the ladder be from the bot
True [87]

Answer:

24 foot

Step-by-step explanation:

We are given that

Length of ladder=26 foot

Height of building=10 foot

We have to find the distance between the bottom of ladder and the bottom of building.

Pythagorus theorem:

(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2

We have hypotenuse =AC=26 foot

Perpendicular side =AB=10 foot

Base=BC

Substitute the values in the given formula

(26)^2=(10)^2+(BC)^2

676=100+(BC)^2

(BC)^2=676-100=576

BC=\sqrt{576}=24 (Take positive because length is always positive)

BC=24 foot

Hence, the bottom of the ladder will be 24 foot  from the bottom of the building.

8 0
3 years ago
f the principal is $350 and the interest rate is 3 percent, what is the simple interest earned in one year?
damaskus [11]

Answer:

$10.50

Step-by-step explanation:

The formula is Balance= Principle (starting amount) x Time x Interest rate. 350 x .03 x 1 is $10.50.

8 0
3 years ago
The area of a room is 600 square feet. The length is (x + 5) feet and the width is (x + 4) feet. Find the dimensions of the room
tangare [24]
I'm going to assume that the room is a rectangle.

The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. 

You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
A = lw\\
600 = (x+5)(x+4)\\
600 =  x^{2} + 9x + 20


Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
600 = x^{2} + 9x + 20\\
x^{2} + 9x - 580 = 0\\
(x + 29)(x - 20) = 0\\
x + 29 = 0, \:\: x - 20 = 0\\
x = -29, x = 20

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.

The dimensions of your room are 25ft (length) by 24ft (width).
8 0
3 years ago
Read 2 more answers
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