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zmey [24]
3 years ago
5

Tell whether the triangle with the given side lengths is a right triangle. 40m, 50m, 60m

Mathematics
1 answer:
EleoNora [17]3 years ago
7 0
It is not because it doesn’t have a length of 90 which is a right triangle
hope this helps
stay safe
brainliest is appreciated, I only need 2 more to level up :))))
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A and B are vertical angles. If m A = (3x+3)° and m B= (4x-8)°, then find the value of x.
iogann1982 [59]

Answer: x=11

Step-by-step explanation:

First, since angle A and angle B are vertical angles, that means that they are congruent. If they are congruent, then the m of angle A equals the measure of angle B. So, (3x+3)=(4x-8). Simplify using algebra so that in the end, you will find that x=11.

3x+3=4x-8

3=x-8

11=x

6 0
3 years ago
PLEASE HELP ASAP!!!!!!!!!!! PLEASE
guapka [62]
Which one the highlight one
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%28a%20%2B%202%20%29%20-%202%20%28a%20-%203%29" id="TexFormula1" title="4(a + 2 ) - 2 (a - 3)
satela [25.4K]

Answer:

\large\boxed{2a+14}

Step-by-step explanation:

4(a + 2 ) - 2 (a - 3)\qquad\text{use distributive property:}\ a(b+c)=ab+ac\\\\=4a+8-2a-(-6)\qquad\text{combine like terms}\\\\=(4a-2a)+(8+6)\\\\=2a+14

5 0
3 years ago
Find the area of a parallelogram if a base and corresponding altitude have the indicated lengths.
Vitek1552 [10]
The answer is 3/4 ft² = 0.75 ft²

The area (A) of the parallelogram with altitude a and base b is:
A = a * b

We have:
A = ?
a = 6 in
Since 1 inch is 0.083 feett, then 6 inches is
a = 6 * 0.083 ft = 0.498 ft ≈ 0.5 ft = 1/2 ft
b = 1 1/2 ft = 1 + 1/2 ft = 2/2 + 1/2 ft = 3/2 ft
_______
A = a * b
a = 1/2 ft
b = 3/2 ft
A = 1/2 * 3/2 = 3/4 ft² = 0.75 ft²
4 0
3 years ago
Select the three statements that are true. A. -11 &gt; -6 B. -5 &gt; -7 C.-4 &gt; -6 D. -9 &gt; 7 E. 8 (-1 F. -5 -4​
OLEGan [10]

Answer: B, C, And F

Step-by-step explanation:

My answer is correct because, for the negative numbber whatever is close to 1 like -1 is greater then the other negative number.

#AnimePower

4 0
2 years ago
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