All categories

4 years ago

Find the 8th term in the sequence. 4, -24, 144, -864,...

Mathematics

2 answers:

jeka57 [31]4 years ago

6 0

Just continue multiplying by -6. The 8th term would be -1119744

snow_lady [41]4 years ago

6 0

Hello here is a solution :

You might be interested in

Help me please and thank you!

mamaluj [8]

7^6 is the correct answer

8 0

3 years ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

3 years ago

Free brainliest ! :)

kodGreya [7K]

Answer:

Thanks!

Step-by-step explanation

Thank you!

8 0

3 years ago

Read 2 more answers

Pls in order to pass i need to finish this pls help and for 4 5 6 and only 9

Yuliya22 [10]

Answer:

7 and 8

7=a

8=b

and sssuree

9=A=100(3.14)

4) not sure butt sure like 70%

area=36(3.14)

5)9(3.14)

6)289(3.14)

hope u pass

7 0

3 years ago

Y = 40 (1.25) Does this equation represent exponential growth<br> or<br> decay?

Tasya [4]

Answer:

Exponential functions are patterns that get continuously multiplied by some number. It's exponential growth when the base of our exponential is bigger than 1, which means those numbers get bigger. It's exponential decay when the base of our exponential is in between 1 and 0 and those numbers get smaller.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers