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laila [671]
3 years ago
13

Which is the graph of y – 3 = (x + 6)?

Mathematics
1 answer:
velikii [3]3 years ago
3 0

The Answer is A (The first graph in the photo), I attached the graph to help you see the answer for y-3=-\frac{2}{3}(x+6).

I hope you have a good day and please give me brainest if that is correct!

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QUiCK whoever gives me the right answer gets brainliest
8_murik_8 [283]

Answer:

speed of R miles per hour

miles depends on time

thats why it's miler per hour

7 0
3 years ago
Ashley sells 18.6 kg bags of mixed nuts that contain 60% peanuts. To make her product she adds peanuts to Brand A's mixed nuts w
slavikrds [6]

Answer:

She combines 9.3 kg of each.

Step-by-step explanation:

Let x = amount of brand A in kg

Let y = amount of peanuts in kg

First we deal with the amount of each product she uses.

"Ashley sells 18.6 kg bags of mixed nuts that contain 60% peanuts."

x + y = 18.6

Now we deal with just the amount of peanuts.

"To make her product she adds peanuts to Brand A's mixed nuts which contain 20% peanuts."

Brand A contains 20% peanuts, so x kg of brand A contains 0.2x kg of peanuts.

The peanuts she adds are pure peanuts, so all of y is peanuts.

The result is 18.6 kg of a mixture that is 60% peanuts, so the amount of peanuts in the bags she sells is 0.6 * 18.6 kg.

0.2x + y = 0.6 * 18.6

0.2x + y = 11.16

We have a system of equations:

x + y = 18.6

0.2x + y = 11.16

We have y in both equations, so let's subtract the second equation from the first equation to eliminate y.

0.8x = 7.44

Divide both sides by 0.8

x = 9.3

Plug in 9.3 for x in the first equation of the system and solve for y.

x + y = 18.6

9.3 + y = 18.6

y = 9.3

Answer: She combines 9.3 kg of each.

4 0
3 years ago
The width of a swimming pool is one third of its length.The width of the pool is 15 feet.What is the length of the pool?Write an
zubka84 [21]
The answer is 45

Here is why: 15*3=45
5 0
3 years ago
Simplify the expression
AlexFokin [52]

Answer:

B

Step-by-step explanation:

\frac{3+4\iota}{2+4\iota}=\frac{3+4 \iota}{2+4\iota} \times \frac{2-4 \iota}{2-4 \iota}\\=\frac{6 -12 \iota+8 \iota-16 \iota^2  }{4-16 \iota^2  }\\=\frac{ 6-4 \iota+16}{4+16}\\=\frac{22-4 \iota}{20}

5 0
3 years ago
M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]

Answer:

Step-by-step explanation:

Given

<LON = 77°

<LOM = (9x+44)°

<MON = (6x+3)°

The addition postulate is true for the given angles since tey have a common point O:

<LON = <LOM+<MON

Since we are not told what to find we can as well look for the value of x, <LOM and <MON

Substitute the given parameters and get x

77 = 9x+44+6x+3

77 = 15x+47

77-47 = 15x

30 = 15x

x = 30/15

x = 2

Get <LOM:

<LOM = 9x+44

<LOM = 9(2)+44

<LOM = 18+44

<LOM = 62°

Get <MON:

<MON = 6x+3

<MON = 6(2)+3

<MON = 12+3

<MON = 15°

6 0
4 years ago
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