X intercept is where the line crosses the x axis or where y=0
y intercept is where the line crosses the y axis or where x=0
so
6x-3y=-6
x intercept
y=0
6x-3(0)=-6
6x=-6
x=-1
x intercept at x=-1 or the point (-1,0)
y intercept
x=0
6(0)-3y=-6
-3y=-6
y=2
y intercept at y=2 or the point (0,2)
Answer:
The answer to this problem is True.
Answer:
Multiply:





Multiply:




Multiply:






Multiply:





Step-by-step explanation:

We need to define our outcomes and events.
Finding the probability<span> of each event occurring
separately, and then multiplying the probabilities is the step to <span>finding
the probability</span> of two
independent events that occur in
sequence.
</span>
<span>
To solve this problem, we take note of this:</span>
The roll of the two dice are denoted by the pair
(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }
Each pair is an outcome. There are 36 pairs and each has
probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has
probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the
number of rolls N until we observe doubles is a geometric (p) random variable
and has expected value E[N] = 1/p = 6.
<h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
If the trapezoid is isosceles, angles A and C are supplementary, so ...
... (4x+4) +(7x+11) = 180
... 11x +15 = 180 . . . . . . collect terms
... 11x = 165 . . . . . . . . . subtract 15
... x = 15 . . . . . . . . . . . . divide by the coefficient of x
And angles C and E are congruent.
... 4·15 +4 = 21y +1
... 63 = 21y . . . . . subtract 1
... 3 = y . . . . . . . . divide by the coefficient of y