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Ainat [17]
3 years ago
14

A newborn baby gained 7/16 of a pound in a 1/2 of a month.what was the baby's growth rate in pounds per month.

Mathematics
1 answer:
swat323 years ago
8 0
If the baby gained 7/16 of a pound in 1/2 a month, you need to multiply 7/16*2 to find how many pounds the baby will grow in one month. 

7/16*2

Cancel 2 and 16<span>.
</span><span>7/8

</span>Exact Form: 
<span>7/8</span> 

<span>Decimal Form: </span>
<span>0.875

The baby gained 7/8 or 0.875 pounds in 1 month</span>
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Estimate 102.3 divided by 4.7
qwelly [4]

Answer:

20

Explanation:

To estimate, we round.  102.3 rounds to 100 and 4.7 rounds to 5; this means we divide 100/5, which is 20.

5 0
3 years ago
Read 2 more answers
brine's kitchen has an area of 81 square feet. the kitchen is 9 times as many square feet as brine's pantry. if the pantry is 3
maks197457 [2]
So 81/9=9 so area of pantry is 9

3 times x=9
3x=9
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legnth/width=3
8 0
3 years ago
A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns​ shown, making the​
Ilya [14]

Answer:

The original selling price would be $ 515.87 ( approx )

Step-by-step explanation:

Let x be the original selling price ( in dollars ),

After marking down 10%,

New selling price = x - 10% of x = x - 0.1x = 0.9x

Again after marking down 30%,

Final selling price = 0.9x - 30% of 0.9x

= 0.9x - 0.3 × 0.9x

= 0.9x - 0.27x

= 0.63x

According to the question,

0.63x = 325

\implies x =\frac{325}{0.63}\approx 515.87

Hence, the original selling price would be $ 515.87.

7 0
3 years ago
What is the difference written in scientific notation? 0.00067 - 2.3 x 10^5
shepuryov [24]
0.00067=67X10^5 so

67X10^5-2.3X10^5

64.7X10^5 which can be expressed as:

6.47X10^6

(not sure if it matters to you or not, but technically we only had two significant figures so it should be rounded to 6.5X10^6)


5 0
3 years ago
Consider the parametric curve:
11Alexandr11 [23.1K]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}=\dfrac{4\sec t\tan t}{3\sec^2t}=\dfrac43\sin t

When t=\pi, we have

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{t=\pi}=\dfrac43\sin\pi=0

7 0
3 years ago
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