we know that
The area of the hexagon is equal to the sum of the areas of the six equilateral triangles
Let
x-------> area of one equilateral triangle
so
Divide by 
both sides
-------> area of one equilateral triangle
To find an equivalent expression for the area of the hexagon based on the area of a triangle, multiply the area of one equilateral triangle by
therefore
the answer is
The equivalent expression is equal to
Answer:
a+b=mx+b
Step-by-step explanation:
If Bobby claims Peter started with 21 cards, then we'll work this into our equation.
21 - 3 (that he lost) = 18
18 / 2 (the half he gave) = 9
So this means that he did have 21 cards to begin with. Please reply to this with a list of the answers that can/could be checked!
Answer:
C = ~50 deg
Step-by-step explanation:
Apply the cosine theorem:
cos(C) = (CA^2 + CB^2 - AB^2)/(2*CA*CB)
= (7.5^2 + 6.5^2 - 6^2)/(2*7.5*6.5)
= 0.6410
=> C = ~50 deg
Hope this helps!
Answer:
Part a)
We need to find the equation of a straight line passing through two given points in slope-intercept form
Part b)
The information given; we are given two points where the line passes through; (0, -4) and (-2, 2)
Part c)
We shall first determine the slope of the line using the formula;
change in y/change in x. Next, we determine the value of the y-intercept using the general form of the equation of a straight line in slope-intercept form; y = mx+c
Part d)
The slope of the line is calculated as;
(2--4)/(-2-0) =6/-2 = -3
The equation of the line in slope-intercept form becomes;
y = -3x +c
We use the point (0, -4) to determine the value of c;
-4 = -3(0)+c
c = -4
Part e)
Final solution thus becomes;
y=-3x-4
