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3 years ago

In the image, point A marks the center of the circle. Which two lengths must form a ratio of 2:1?

Mathematics

2 answers:

Elza [17]3 years ago

6 0

Answer:

option b. $EF:AD=2:1$

Step-by-step explanation:

we know that

In a circle the ratio of the diameter to the radius is equal to $2:1$

because

$D=2r$

$2r/r=2:1$

In this problem

EF is a diameter

AD is a radius

therefore

$EF:AD=2:1$

harina [27]3 years ago

5 0

I hope this helps you

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It looks like the differential equation is

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We have

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