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Rainbow [258]
3 years ago
12

Nate draws a map to show locations on a playground.

Mathematics
1 answer:
o-na [289]3 years ago
7 0

i think that it is 1 yard because they are 1 apart

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Find the sum of -6/ab + a^2/b^2
Ymorist [56]

Answer:

\frac{1}{ab^{2} } (a³ - 6b)

Step-by-step explanation:

\frac{-6}{ab} + \frac{a^{2} }{b^{2} }

= \frac{-6b + a^{3} }{ab^{2} }

= \frac{1}{ab^{2} } (a³ - 6b)

4 0
3 years ago
X+2y=-1 and 4x-4y=20 solve by substitution
Illusion [34]

To do this problem you would first need to factor out a variable, which in this case I would want to do the first equation because it is isolated. Now the equations would look like this:

x = -2y - 1

4x - 4y = 20

Since we know that x is now equal to -2y - 1 we can plug it in to the x value in the second equation:

4 (-2y -1) - 4y = 20

-8y -4 - 4y

-12y - 4 = 20

-12y = 24

y = -2

Now that we know the y value plug the y value to one equation to find the x, I will be using the first equation

x + 2(-2) = -1

x - 4 = -1

x = 3

Solutions:

y = -2

x = 3

8 0
3 years ago
If you can help press on this
GenaCL600 [577]
It is rational because any number that can be represented in a fraction is rational. 4/33 is a fraction, so it is rational.
8 0
3 years ago
52 POINTS, WILL GIVE BRAINLIEST!
harkovskaia [24]

Answer:

The answer is in the attachment.

Step-by-step explanation:

Look at the picture.

7 0
3 years ago
Read 2 more answers
In a cash drawer there is $125 in $5 and $10 bills. The number of $10 bills is twice the number of $5 bills. How many of each ty
WINSTONCH [101]

Let us take number of $5 bills = x and

                   number of $10 bills  = y.

Give that "number of $10 bills is twice the number of $5 bills".

So, y is twice of x,

We can setup an equation.

y= 2x                      ............................... equation(1)

Total value of all bills = $125.

We can setup another equation,

5*(number of $5 bills) + 10*(number of $10 bills) =125.

5(x) +10(y) = 125                         ................................... equation(2)

Plugging y=2x in equation(2), we get

5(x) +10(2x) = 125   .

5x+20x = 125.

Adding like terms

25x = 125

Dividing both sides by 25.

25x /25 = 125/25

x= 5.

Plugging x=5 in first equation, we get

y= 2(5) = 10.

Therefore, number of number of $5 bills=5 bills  and number of $10 bills = 10 bills.


5 0
3 years ago
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