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vodka [1.7K]
3 years ago
12

Factor x3 + x2! Thanks!

Mathematics
1 answer:
kogti [31]3 years ago
5 0
To factor this take a common multiple. In this case, it is x^2:

x^2(x+1)

Hope this helped!
You might be interested in
In autumn a tree starts to shed its leaves. 2/5 of the leaves fall off in the first week. 1/2 of those remaining fall of in the
Oduvanchick [21]

Answer:

850 leaves were on the tree initially.

Same as;

2/5 + 1/5 + 3/10 + (remaining leaves 1/10) = 1

4/10 + 2/10 + 3/10 + 1/10

10 x 85 = 850

Step-by-step explanation:

2/5  wk 1 fall off

1/5  wk 2 fell off

3/5 x 1/2  = 3/10 wk 2 stayed on tree

1/3 x 3/10 = 1/10 wk 3 stayed on

2/5 + 1/5 + 3/10 = 9/10 =  0.9 fall off in total

10/10 - 9/10 = 1/10 left on tree

1/10 = 85

10 x 85 = 850 leaves.

8 0
2 years ago
Can you please help me on 6(1+n)=8n-3(n-7)
Nana76 [90]

Answer:

n = 15

Step-by-step explanation:

6(1+n)=8n-3(n-7)

Distribute

6 +6n = 8n -3n +21

Combine like terms

6+6n = 5n +21

Subtract 5n from each side

6+6n-5n = 5n-5n +21

6 +n = 21

Subtract 6 from each side

6-6+n = 21-6

n = 15

3 0
3 years ago
Amir encoded a secret phrase using matrix multiplication.
shtirl [24]

This is the question

4 0
3 years ago
(25 points, please help! Brainliest!) Mrs. Hanger is painting the following picture of an H to hang in the entryway of her home.
disa [49]

Answer:

the new scale is the same length as the original scale

7 0
2 years ago
The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow
Reika [66]
If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now    \bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
0=\frac{3w^2-6000000}{w^2}
\end{cases}

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the 0=w^2\implies 0=w   so.  you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0
3 years ago
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