Answer:
Step-by-step explanation:
For example, if f(x) = 2x + 7
then f(-3) = 2(-3) + 7
f(-3) = 1
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
The slope-intercept form:
m - slope
b - y-intercept
The formula of a slope:
We have two points (2, 0) and (-2, -4). Substitute:
Therefore we have the equation of a line
Put the coordinates of the point (2, 0) to the equation:
<em>subtract 2 from both sides</em>
Answer: 
I’m sorry I don’t know the length of JT however JE = 3.
