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3 years ago

What is median height of 72, 75, 78, 72, and 73?

2 answers:

6 0

The median height is the one in the middle when placed in numerical order. Which in this case, it is 73. (the bolded numbers are those that are being crossed out)

72, 72, 73, 75, 78
72, 72, 73, 75, <span>78
</span>72, 72, 73, 75, 78

73 is the median height!

ladessa [460]3 years ago

5 0

The answer is 73 because to find the median you line them up least to greatest which looks like this, 72, 72, 73, 75, 78 and as you can see 73 is the number in the middles hope this helps! :D
V
(72, 72,) 73,(75, 78)

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Which of the following expressions are factors of p(x)=60x4+24x3−45x2−18x?

Whitepunk [10]

The factors are 3x, 4x^2-3 and 5x+2

So, Option B, C and F are correct.

Step-by-step explanation:

We need to find factors of the expression $p(x)=60x^4+24x^3-45x^2-18x$

Solving the expression: $p(x)=60x^4+24x^3-45x^2-18x$

Taking 3x common:

$p(x)=3x(20x^3+8x^2-15x-6)$

Now, factor by grouping, the terms inside the bracket.

$p(x)=3x((20x^3+8x^2)+(-15x-6))$

$p(x)=3x(4x^2(5x+2)-3(5x+2))$

$p(x)=3x(4x^2-3)(5x+2)$

So, the factors are 3x, 4x^2-3 and 5x+2

So, Option B, C and F are correct.

Keywords: Finding Factors

Learn more about finding factors at:

#learnwithBrainly

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3 years ago

how many times as much water will a rectangular tank that measures 2 ft by 6 ft by 8 ft hold than a rectangular tank that measur

Ivanshal [37]

Answer:

water nugget

Step-by-step explanation:

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3 years ago

Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).

Firdavs [7]

Answer:

A) Particular solution:

$2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

B) Homogeneous solution:

$y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))$

C) The most general solution is

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$

The general solution is

$y=y_{h}+y_{p}$

from (2) ad (3)

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

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3 years ago

What is the fraction 70/75 equivalent to?

ki77a [65]

Answer:14/15

Step-by-step explanation:

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3 years ago

What is a true statement about negative exponents?

Nadya [2.5K]

Answer:

Raising something to a negative exponent is just taking the reciprocal of the amount.

Step-by-step explanation:

Let's assume that you wanted to know what $x^{-2}$ is.

To find it, you would take the reciprocal of the x amount. So $x^{-2}$ becomes $\frac{1}{x^{2}}$ .

This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So $a^{3}$ would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase $a^{3}$ to $a^{5}$ , you would have to multiply a with $a^{3}$ two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease $a^{5}$ to $a^{2}$ , you would have to divide $a^{5}$ by a 3 times.

If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: $\frac{1}{a^{3}}$ means that you are dividing 1 by a 3 times.

Hope this helps.

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3 years ago