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3 years ago

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align="absmiddle" class="latex-formula"> [tex] \frac{4}{-9} [/tex^2]
When two fractions are right beside each other like this in a parentheses, does that mean u multiply them??

1 answer:

tatuchka [14]3 years ago

6 0

Although the equation didn't come out right, yes when two number are covered in parenthesis it means to multiply them
E.g. (2)(2) or (1/2)(1/2)

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Given a required reserve ratio of 10 percent for all banks, total bank reserves of $400 billion could support maximum deposits o

serious [3.7K]

Answer:

The maximum deposit is $4,000 billion.

Step-by-step explanation:

Consider the provided information.

It is given that the required reserve ratio of 10 percent for all banks.

It is given that total bank reserves of $400 billion.

Let the maximum deposit is x.

Therefore, 10% of x = $400 billion

$\frac{10}{100}\times x=\$400\text{ billion}$

$x=\frac{100}{10}\times \$400\text{ billion}$

$x=10\times \$400\text{ billion}$

$x=\$4000\text{ billion}$

Hence, the maximum deposit is $4,000 billion.

8 0

4 years ago

1. Find the inverse of the one-to-one function f(x)= 6x-7 / 5

Elenna [48]

Rewrite it as y=6x-7/5

Flip the x and y
x=6y-7/5

Solve
5x=6y-7
5x+7=6y
5/6x+7/6=y

f^-1(x)=5/6x+7/6

4 0

3 years ago

Using Cramer’s Rule, what is the value of y in the system of linear equations below?

Vadim26 [7]

for the system of equations

$a_1x+b_1y=c_1 \\a_2x+b_2y=c_2$

the three matrices needed to use Cramer's Rule are:

$D=\left[\begin{array}{cc}a_1&b_1\\a_2&b_2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}c_1&b_1\\c_2&b_2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}a_1&c_1\\a_2&c_2\end{array}\right]$ .

To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.

$D=\left[\begin{array}{cc}2&5\\-3&-2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}-13&5\\3&-2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}2&-13\\-3&3\end{array}\right]$ .

The value of the determinants are shown below.

$det(D)=(2)(-2)-(-3)(5)=-4+15=11\\det(D_x)=(-13)(-2)-(3)(5)=26-15=11\\det(D_y)=(2)(3)-(-3)(-13)=6-39=-33\\$

The value of y is $\frac{det(D_y)}{det(D)}=-\frac{33}{11} =-3.$ .

3 0

4 years ago

Solve the following equation; domain 0< x < 360; 3 cot x + sqrt 3 = 0

kondaur [170]

ANSWER

$x =120 \degree \: or \: 300 \degree$

EXPLANATION

We want to solve the trigonometric equation

$3 \cot(x) + \sqrt{3} = 0$

We group like terms to obtain,

$3\cot(x) = - \sqrt{3}$

Divide both sides of the equation by 3 to get,

$\cot(x) = - \frac{ \sqrt{3} }{3}$

We can reciprocate both sides to get,

$\tan(x) = - \frac{3}{ \sqrt{3} }$

We simplify the right hand side to get,

$\tan(x) = - \sqrt{3}$

Since the tangent ratio is negative, it implies that it is either in the second quadrant or fourth quadrant.

In the second quadrant,

$x = 180 \degree - arctan( \sqrt{3})$

$x = 180 \degree - 60 \degree = 120 \degree$

In the fourth quadrant,

$x = 360 \degree - arctan( \sqrt{3})$

$x = 360 \degree - 60 \degree$

$x = 300 \degree$

6 0

4 years ago

Select the correct answer.

yaroslaw [1]

Answer:

<h2>D. </h2><h2>{x | x = all real numbers}</h2>

Step-by-step explanation:

The domain of a function is the set of input or argument values for which the function is real and defined.

The function has no undefined points nor domain constraints. Therefore, the domain is

$-\infty \:$

$\mathrm{Domain\:of\:}\:2\left|x-1\right|+3\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

4 0

3 years ago