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3 years ago

What are the solutions of 2x2 + 3x = -5

Mathematics

2 answers:

Daniel [21]3 years ago

7 0

$2x^2 + 3x = -5\\2x^2 + 3x +5=0\\ \Delta=3^2-4\cdot2\cdot5=9-40=-31\\\\\Delta$

Dvinal [7]3 years ago

5 0

X=-3 since 4 + 3x = -5 then subtracting 4 on each sides you get that 3x = -9 and so x=-9/3 which is equal to -3.

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Exercises 1-3, tell which equation you would choose to solve for one of the variables. Explain.

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Answer:

1, because you can subtract both equations to eliminate y , and you will be left with only x.

Step-by-step explanation:

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3 years ago

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11. Rocco and Biff are two koalas sitting at the

bagirrra123 [75]

Answer:

Biff's tree is 14 m off the ground and Rocco's tree is 7 m off the ground.

Step-by-step explanation:

Let the height of Biff's tree be represented by x, so that the height of Rocco's tree is $\frac{x}{2}$ .

Draw a straight line from Rocco's point of view to a point t to the middle of Biff's tree. This line divides x into two equal parts, and the angle is divided into $35^{0}$ each.

By alternate angle property,

Tan $35^{0}$ = $\frac{\frac{x}{2} }{10}$

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= 7.00021

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3 years ago

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Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.