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Naya [18.7K]
3 years ago
13

Ellen drove 357.3 miles.for each gallon of gas,the car can travel 21 miles.select a reasonable estimate of the number of gallons

of gas Ellen used.
Mathematics
1 answer:
kari74 [83]3 years ago
7 0
Just a little over 17 gallons was used
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4x +6 < -6 show steps​
rewona [7]
4x + 6 < -6
- 6 -6

4x < -6
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4 4

x < -1.5
6 0
3 years ago
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mark ordere wome balloons for a party that she is having.The balloons cost $4.50 each and there is a service fee of $12.The tota
ohaa [14]
A general equation to use for this situation is y = mx + b.

For this question, we can assume that y is total cost, m is cost per balloon, x is the amount of balloons, and b as the service fee; so we can set the equation up:

y = (4.50)x + 12

And we can further plug in the total cost to find the number of balloons purchased for the party:

79.50 = (4.50)x + 12

Now we can solve for x (number of balloons):

67.50 = (4.50)x

x = 15

The total number of balloons purchased for the party is 15.
5 0
3 years ago
Please help me. What are 2 numbers that multiply to be -36 and add up to be 5?
elena55 [62]

Answer:

-4 and 9

Step-by-step explanation:

-4 + 9 = 5

-4 x 9 = -36

4 0
3 years ago
Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

Download docx
6 0
3 years ago
The perimeter of a stop sign is 96
Fittoniya [83]

Answer:

x = 44

Step-by-step explanation:

4+4+2x+2x= 96

-(add like terms)

8+4x=96

-(subtract 8 from both sides)

4x=88

-(divide by 4 on both sides to get you x alone)

x=44

4 0
3 years ago
Read 2 more answers
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