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ollegr [7]
3 years ago
9

Write the equation 8y = 1/12 x – 0.8 in standard form. Identify A, B, and C.

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

The equation is 10x - 960y = 96

A = 10 , B = -960 , C = 96

Step-by-step explanation:

* Lets explain the standard form of the linear equation

- The standard form of the linear equation is :

 AX + BY = C , where A , B , C are constant

- A is a positive integer, and B, and C are integers

- The slope of the line is -A/B

- The y-intercept is C/A

- Lets solve the problem

∵ The equation of the line is 8y = 1/12 x - 0.8

- At first multiply the equation by 12 to make the coefficient of x integer

∴ (8 × 12) y = (1/12 × 12) x - (0.8 × 12)

∴ 96y = x - 9.6

- Multiply the two sides of the equation by 10 to make 9.6 integer

∴ (96 × 10) y = (1 × 10) x - (9.6 × 10)

∴ 960y = 10x - 96

- Add the two sides by 96

∴ 960y + 96 = 10x

- Subtract 960y from both sides

∴ 96 = 10x - 960y

∴ The standard form of the equation is 10x - 960y = 96, where

  A = 10 , B = -960 , C = 96

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ahrayia [7]
Yes you got them all correct at least I think.
5 0
3 years ago
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Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2
kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}

Multiply -y+x=2 by 2:  -2y+2x=4

\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}

so adding

-2y+2x=4

+

\underline{2y-2x=7}

0=11

so the system of equations becomes

\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0
3 years ago
A circle with radius of 3 cm sits inside a circle with radius of 5 cm. What is the area of the shaded region? Round your final a
DiKsa [7]

Hello!!

So first you need to find the area of the green circle. The formula for finding area for a circle is A = π r2. So the area for the green circle is 28.26 cm. Then you need to find the area of the blue circle. (Using the same formula) which would be 78.5. Then you subtract the value of the green circle to get the value of the shaded region which then your final answer is 50.24 cm. Hope this helped!!

8 0
3 years ago
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What is the next number in the sequence below?
zysi [14]
Answer is
B. 6
It’s dividing by 2
3 0
3 years ago
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Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?
zlopas [31]

Answer:

Let be a rational complex number of the form z = \frac{a + i\,b}{c + i\,d}, we proceed to show the procedure of resolution by algebraic means:

1) \frac{a + i\,b}{c + i\,d}   Given.

2) \frac{a + i\,b}{c + i\,d} \cdot 1 Modulative property.

3) \left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)   Existence of additive inverse/Definition of division.

4) \frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}   \frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}  

5) \frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}  Distributive and commutative properties.

6) \frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)} Distributive property.

7) \frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}} Definition of power/Associative and commutative properties/x\cdot (-y) = -x\cdot y/Definition of subtraction.

8) \frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}} Definition of imaginary number/x\cdot (-y) = -x\cdot y/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form z = \frac{a + i\,b}{c + i\,d}, we proceed to show the procedure of resolution by algebraic means:

1) \frac{a + i\,b}{c + i\,d}   Given.

2) \frac{a + i\,b}{c + i\,d} \cdot 1 Modulative property.

3) \left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)   Existence of additive inverse/Definition of division.

4) \frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}   \frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}  

5) \frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}  Distributive and commutative properties.

6) \frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)} Distributive property.

7) \frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}} Definition of power/Associative and commutative properties/x\cdot (-y) = -x\cdot y/Definition of subtraction.

8) \frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}} Definition of imaginary number/x\cdot (-y) = -x\cdot y/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

3 0
2 years ago
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