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sleet_krkn [62]
3 years ago
14

Given the vectors, a=3i+4j, b=-2i+5j, c=10i-j, d=-1/3i+5/2j, find -0.4a-0.3b+0.2d=?

Mathematics
1 answer:
sveta [45]3 years ago
6 0

Answer:

-\frac{2}{3}i - \frac{13}{5}j

Step-by-step explanation:

-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(-\frac{1}{3}i + \frac{5}{2}j)

-1.2i - 1.6j + 0.6i - 1.5j - \frac{0.2}{3}i + 0.5j

Converting to fraction form;

-\frac{6}{5}i + \frac{3}{5}i - \frac{1}{15}i - \frac{8}{5}j - \frac{3}{2}j + \frac{1}{2} j

<u>Solving the i part;</u>

\frac{-18i + 9i - i}{15} = -\frac{2}{3}i

<u>Solving the j part;</u>

\frac{-16j-15j+5j}{10} = -\frac{13}{5}j

So -0.4a - o.3b + 0.2d =  -\frac{2}{3}i - \frac{13}{5}j

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3 0
3 years ago
A type of organism's cells split every minute. If the organism has 4 cells when the cells begin to split, how many cells will th
snow_lady [41]

Answer:

The total of cells will the organism have after 6 minutes is 252

Step-by-step explanation:

* Lets consider this problem as a geometric series

- There is a constant ratio between each two consecutive numbers

Ex:

# 5  ,  10  ,  20  ,  40  ,  80  ,  ………………………. (×2)

# 5000  ,  1000  ,  200  ,  40  ,  …………………………(÷5)

* General term (nth term) of a Geometric series:

∵ U1 = a  ,  U2  = ar  ,  U3  = ar^2  ,  U4 = ar^3  ,  U5 = ar^4

∴ Un = ar^n-1

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* The sum of first n terms of a Geometric Progression is calculate from

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- In the problem the cell split every minute

- The organism has 4 cells when the cells begin to split

∴ a = 4

# 4 , 8 , 16 , 32 , .......

∴ r = 2

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  calculate from the rule of the sum

∴ S6 = 4(1 - 2^6)/1 - 2 = 4(1 - 64)/-1 = 4(-63)/-1 = 252 cells

4 0
3 years ago
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