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ExtremeBDS [4]
3 years ago
12

What’s the sum of the measures of the exterior angles of a 53-gon?

Mathematics
2 answers:
kondor19780726 [428]3 years ago
7 0
The answer is A) 6.8 degrees
fredd [130]3 years ago
4 0
Equation:
360/n
n = 53

Answer:
360/53 = 6.8
(A)

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How are the graphs of the functions f(x) = and g(x) = related?
RSB [31]
The x variable, that is being multiplied.
4 0
3 years ago
Hey could someone please help me with this really hard assignment is taking me forever. Thank you marking brainliest!
rewona [7]

Answer:

Exercise 1: The length of the unknown leg is 4 inches.

Exercise 3: The following straws can be used to construct the triangle: b) 3\,in, c) 4.5\,in, d) 6.5\,in, e) 10\,in, f) 13.5\,in

Exercise 4: Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

Step-by-step explanation:

Exercise 1:

Let suppose that triangle represented in the figure is a right triangle, the length of the missing leg is determined by Pythagorean Theorem:

y = \sqrt{l^{2}-x^{2}} (1)

Where:

l - Hypotenuse, in inches.

x - Known leg, in inches.

y - Unknown leg, in inches.

If we know that l = 11\,in and x = 10\,in, then the length of the unknown leg is:

y = \sqrt{21}

Since 4 is the least whole number closest to \sqrt{21}, then we conclude that the length of the unknown leg is 4 inches.

Exercise 3:

The range of possible lengths for the missing side of the triangle is represented by the following simultaneous inequality:

x + y > l > x-y (2)

Where:

x - Greater side, in inches.

y - Lesser side, in inches.

l - Missing side, in inches.

If we know that x = 8\,in and y = 6\,in, then we have the following range of missing sides:

14\,in > l > 2\,in

The following straws can be used to construct the triangle: b) 3\,in, c) 4.5\,in, d) 6.5\,in, e) 10\,in, f) 13.5\,in

Exercise 4:

Let check each pair to determine possible constructions by means of the inequality used in Exercise 3:

(i) x = 4\,in, y = 2\,in

6\,in>l>2\,in

Possible choices: 5 inches.

(ii) x = 5\,in, y = 2\,in

7\,in > l > 3\,in

Possible choices: 4 inches, 6 inches.

(iii) x = 6\,in, y = 2\,in

8\,in > l > 4\,in

Possible choices: 5 inches, 6 inches.

(iv) x = 10\,in, y = 2\,in

12\,in > l > 8\,in

Possible choices: None.

(v) x = 5\,in, y = 4\,in

9\,in > l > 1\,in

Possible choices: 2 inches, 6 inches.

(vi) x = 6\,in, y = 4\,in

10\,in > l > 2\,in

Possible choices: 5 inches.

(vii) x = 10\,in, y = 4\,in

14\,in > l > 6\,in

Possible choices: None.

(viii) x = 6\,in, y = 5\,in

11\,in > l > 1\,in

Possible choices: 2 inches, 4 inches, 10 inches.

(ix) x = 10\,in, y = 5\,in

15\,in > l > 5\,in

Possible choices: 6 inches.

(x) x = 10\,in, y = 6\,in

16\,in > l > 4\,in

Possible choices: 5 inches.

Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

7 0
2 years ago
Read 2 more answers
Assume we cut the last piece of the pie into two sections (1 and 2) along ray BD
earnstyle [38]

Answer:

If we want the greatest portion of pie, then you must choose the section with the greatest angle. Therefore, we must choose Section 2. But if we want the smallest portion of pie, then we must choose Section 1.

Step-by-step explanation:

From statement, we know that measure of the angle ABC is equal to the sum of measures of angles ABD (<em>section 1</em>) and DBC (<em>section 2</em>), that is to say:

m \angle ABC = m\angle ABD + m\angle DBC (1)

If we know that m\angle ABC = 40^{\circ}, m\angle ABD = 2\cdot x + 3 and m\angle DBC = 4\cdot x + 7, then the value of x is:

(2\cdot x + 3)+(4\cdot x + 7) = 40^{\circ}

6\cdot x +10^{\circ} = 40^{\circ}

6\cdot x = 30^{\circ}

x = 5

Then, we check the angles of each section:

Section 1

m\angle ABD = 2\cdot x + 3

m\angle ABD = 13^{\circ}

Section 2

m\angle DBC = 4\cdot x + 7

m\angle DBC = 27^{\circ}

If we want the greatest portion of pie, then you must choose the section with the greatest angle. Therefore, we must choose Section 2. But if we want the smallest portion of pie, then we must choose Section 1.

6 0
3 years ago
(2a divided by 7) - (a-4)
Shkiper50 [21]

Answer:

a=28/5 or 5.6

Step-by-step explanation:

2a/7=a-4

Multiple both sides of the equation by 7

2a=7a-28

Subtract 7a from both side

2a-7a=-28

Like Term

-5a=-26

Divide -5 from both side

a= 5.6

6 0
3 years ago
School guidelines require that there must be at least 2 chaperones for every 25 students going on a school trip. How many chaper
noname [10]
25 students got 2 chaperones
so 1 will get 2/25

and thus 8 will get 2/25×8 = 0.64 chaperone

but is it possible?? No chaperone can not be in decimal so at least 1 is required !!
3 0
3 years ago
Read 2 more answers
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