Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
<span>3,-6,12,-24,48,-96,192,-384,768,-1536
sum:
</span>3 -6+12 -24+ 48 -96+ 192 -384+ 768 -1536 = -1023
Answer is C. -1023
Answer:
A. 502.4 cm^3
Step-by-step explanation:
r=8/2=4 cm
V=pi*r^2*h=3.14*16*10=502.4 cm^3 (A)
To find the total cost multiply $12 x 180 square feet
Answer:
778%, 7.42, and V48
Step-by-step explanation:
I think that is right
