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3 years ago

For what value k the pair of linear equations 4x-3y=9 and 2x+ky=11 has no solution

Mathematics

1 answer:

yarga [219]3 years ago

8 0

Answer: k=-3/2

Step-by-step explanation:

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Using the information in the Box-and-Whisker plot below, what is the 1st

gizmo_the_mogwai [7]

Answer:

B. 12.5

Step-by-step explanation:

where the box ends on the left side is the 1st quartile.

4 0

2 years ago

Find the length of the third side of the right triangle. Give an exact answer and an approximation to three decimal places if ne

trasher [3.6K]

Answer:

a = 32

Step-by-step explanation:

This is a right triangle and the square value of hypotenuse is equal to sum of square value of other two side lengths

68^2 = 60^2 + a^2

4624 = 3600 + a^2

4624 - 3600 = a^2

1024 = a^2 find the root for both sides

32 = a

8 0

2 years ago

What is an equation of the line that passes through the point (3,-1) and (8, 9)?

Evgesh-ka [11]

Answer:

4) y = 2x - 7

Step-by-step explanation:

First we have to find the slope by using the following formula....

let (3, - 1) be $(x_{1}, y_{1} )$ , let (8, 9) be $(x_{2} ,y_{2} )$ , and m be the slope, then....

$m = \frac{y_{2} -y_{1} }{x_{2} - x_{1} } = \frac{9 + 1}{8 - 3} = \frac{10}{5} = 2$

Now that we know the slope we can find the equation of the function by using point-slope for of the function which look like this.....

$y -y_{1} = m(x - x_{1} )\\y + 1 = 2(x - 3)\\y + 1 = 2x - 6\\y = 2x - 7$

3 0

3 years ago

Convert to a fraction in simplest terms: .45

photoshop1234 [79]

Answer:

9/20

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find a function where f(0)=2 and f(1)=2

xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

$f(x) = 2$ is a valid solution.

Want something more fun? Why not a parabola? $f(x)= ax^2+bx+c$ .

At this point you have three parameters to play with, and from the fact that $f(0)=2$ we can already fix one of them, in particular $c=2$ . At this point I would recommend picking an easy value for one of the two, let's say $a= 1$ (or even $a=-1$ , it will just flip everything upside down) and find out b accordingly: $f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1$

Our function becomes

$f(x) = x^2-x+2$

Notice that it works even by switching sign in the first two terms: $f(x) = -x^2+x+2$

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need $A= 2$ , and at that point the first condition is guaranteed; using the second to find k we get $2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi$

$f(x) = 2cos(2\pi x)$

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

$f(x)= 2+sin(2\pi x)$

Sky is the limit.

8 0

2 years ago