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AysviL [449]
2 years ago
12

What is 4b + 6 ≤ 18. I don't know how to solve it and don't know the answer.

Mathematics
1 answer:
wolverine [178]2 years ago
6 0

Answer:

b≤3

Step-by-step explanation:

For this problem, you want to solve it similarly to linear equations.

We start with 4b+6≤18.

Subtracting 6 from both sides gives 4b≤12.

From there, in order to isolate the b, we must divide both sides by 4, leaving b≤3.

**This content involves solving linear inequalities, which you may wish to revise. I'm always happy to help!

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the height of a kicked soccer ball is represented by the function f(x)=8x-2x^2 where x is the number of seconds since the ball w
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Answer:

Result at time x = 4 seconds the soccer ball hit the ground.

Step-by-step explanation:

At the moment just before the ball is kicked, it is on the ground and so the height f(x) is zero meters. After the kick, the ball goes through the air and it's path can be described by a (mountain) parabola.

So lets see after how many second (x) the height = 0 once again.

f(x) = 8x-2x^2

f(x) = 0

8x - 2x^2 = 0

Try to write the formula in two terms

-2x * (x - 4) = 0

When a product of two or more terms equals zero, then at least one of the terms must be zero.

Now solve each term = 0 separately, meaning, solve as many equations as there are terms in the product.

Any solution of term = 0 solves product = 0.

Solve the first term:

-2x = 0

Multiply left an right from the = singn with the factor -1 gives this outcome:

2x = 0

x = 0

Solve the second term:

x-4 = 0

x = 4

Result at time x = 4 seconds the soccer ball hit the ground.

x = 4

x = 0

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2 years ago
Given that AB parallels QR, AB bisects AE, QR bisects QT
enyata [817]

Answer:

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Step-by-step explanation:

We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:

  1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

  2. Translate A' to Q

The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.

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