Question

I got the question wrong :(

Answer 1

$\bf n~~~+\stackrel{\textit{10 less than twice "n"}}{2n-10}=38\implies 3n-10=38\implies 3n=48 \\\\\\ n=\cfrac{48}{3}\implies \boxed{n=16}\quad \qquad \stackrel{\textit{10 less than twice "n"}}{2(16)-10}\implies 32-10\implies \boxed{22}$