Find the slope of the line shown on the graph to the right (-4,-3) and (2,3)

Mathematics

2 answers:

coldgirl [10]3 years ago

6 0

Answer:

m = 1

Step-by-step explanation:

Use the equation $m=\frac{y2-y1}{x2-x1}$ to find the slope.

next, the equation should look like: $y=\frac{3+3}{2+4}$

Next you should get the equation: $m = \frac{6}{6}$

Finally, just divide 6/6 and the answer will be m = 1

DerKrebs [107]3 years ago

5 0

Answer:

y=x+1

Step-by-step explanation:

to do this we have to use the slope formula, Rise/Run which is (y2-y1)/(x2-x1) so (3-(-3) or 3+3 divided by (2-(-4) or 2+4, so the slope would be 6/6 or 1. so it is up one over one, and since at the x coordinate of 0 it is y=1 we know the formula must be y=x+1

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Secant RM intersects secant RN at point R. Find the length of RQ. If necessary, round to the hundredths place.

QveST [7]

Answer:

3 Units

Step-by-step explanation:

Secant RM intersects secant RN at point R.

The secants intersects the circle at points P and Q respectively as seen in the diagram.

To determine the length of RQ, we use the Theorem of Intersecting Secants.

Applying this on the diagram, we have:

RP x RN=RQ X RM

4(4+5)=RQ(RQ+9)

Let the length of RQ=x

$4*9=x^2+9x\\36=x^2+9x\\x^2+9x-36=0\\x^2+12x-3x-36=0\\x(x+12)-3(x+12)=0\\(x+12)(x-3)=0\\x+12=0$ x-3=0\\x=-12 or x=3\\Since x cannot be negative$\\x=|RQ|=3$