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galben [10]
2 years ago
7

Plz help my daughter she can't figure it out plz help her

Mathematics
1 answer:
Dafna11 [192]2 years ago
6 0

Answer: 3

Step-by-step explanation: First, we have the fraction 1/3.

Next, the word "of" tells us that we need to multiply.

Lastly, we have 9.

So we will multiply 1/3 x 9.

Whenever you have a fraction without a denominator, it means the exact same thing as putting that fraction over 1.

So 9 is the same thing as 9/1.

So we have 1/3 x 9/1.

When multiplying 2 fractions together, we multiply across the numerators and we also multiply across the denominators.

So 1/3 x 9/1 is 9/3 is 9/3.

Notice however that 9/2 is not in lowest terms so we divide the numerator and denominator by 3 to get the

equivalent fraction 3/1 or just 3.

So 1/3 of 9 is 3.

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Please help!! thank you.
Zina [86]

(A) Product of -2x^{3}+x-5 and x^{3}-3x-4 is:

(-2x^{3}+x-5)(x^{3}-3x-4)

=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)

=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)

=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20

=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20

=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20

(B) Yes.

Product of -2x^{3}+x-5 and x^{3}-3x-4 = Product of x^{3}-3x-4 and -2x^{3}+x-5 because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.



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What is length?define​
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