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3 years ago

5

The large rectangle shown consists of five congruent small rectangles. The longer dimension of the large rectangle is 15 mm. Wha

t is the area of one of the small rectangles?

1 answer:

joja [24]3 years ago

6 0

Could you include a picture?

You might be interested in

If the area of a rectangle is

dangina [55]

Answer:

Step-by-step explanation:

width = area ÷ length = 5x+3

6 0

3 years ago

What is the answer to this question? <br> (The one in the middle)

Delicious77 [7]

Let f=number of field goals and a=number of points after.
a+f=38
a+3f=70
.
a+3f=70

a+ f=38
-------subtract
2f=32
.
f=16 field goals he kicked last season.

4 0

4 years ago

What is the slope of the line?

Valentin [98]

Answer:

The slope is three

Step-by-step explanation:

count up from the bottom point until you reach -1 then go over one and you will get 3/1.

3 0

3 years ago

Read 2 more answers

What is the line that passes through points 6,9 and 11,2

Zepler [3.9K]

The final equation of line passing through (6,9) and (11,2)

$y=-\frac{7}{5}x+\frac{87}{5}$

Further explanation:

The general form of equation is:

$y=mx+b$

We have to find the slope first

$m=\frac{y_2-y_1}{x_2-x_1}\\Here\\(x_1,y_1)=(6,9)\\(x_2,y_2)=(11,2)\\Putting\ the\ values\\m=\frac{2-9}{11-6}\\=-\frac{7}{5}$

Putting the value of m in general form

$y=-\frac{7}{5}x+b$

For finding the value of b, putting (6,9) in equation

$9=-\frac{7}{5}(6)+b\\9=-\frac{42}{5}+b\\9+\frac{42}{5}=b\\b=\frac{45+42}{5}\\$

$b=\frac{87}{5}$

Putting the values of b and m

The final equation of line passing through (6,9) and (11,2)

$y=-\frac{7}{5}x+\frac{87}{5}$

Keywords: Equation of line, Slope

Learn more about equation of line at:

#LearnwithBrainly

5 0

3 years ago

. In the design of an electromechanical product, 12 components are to be stacked into a cylindrical casing in a manner that mini

Harlamova29_29 [7]

Answer:

(a) 479,001,600 combinations (b) 95,040 combinations (c) 3,326,400 combinations

Step-by-step explanation:

(a) In the case we have 12 different elements to stack, the possible combinations can be calculated as a premutation of 12 elements:

P = 12! = 479,001,600 combinations

(b) If seven components are identical, we have a permutation with repetition.

We have 7!=5040 combinations that are the same, so there is only one unique out of 5040 combinations. We have to divide the total possible combinations by 5040.

P = 12! / 7! = 479,001,600 / 5,040 = 95,040 combinations

(c) In the same way, if we have 3 components of Type 1 and 4 components of Type 2 (and the others all different), we have 3!*4! = 144 combinations that are the same.

P = 12!/(3!*4!) = 479,001,600 / 144 = 3,326,400 combinations

3 0

4 years ago