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3 years ago

5

The large rectangle shown consists of five congruent small rectangles. The longer dimension of the large rectangle is 15 mm. Wha

t is the area of one of the small rectangles?

1 answer:

joja [24]3 years ago

6 0

Could you include a picture?

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If 9x83=747 then 747+9+83=?

strojnjashka [21]

Answer:

747+9+83=839

Step-by-step explanation:

We can use 9x83=747 as a extra help to get the answer. Say you need the answer above (which I gave you) so you get 9x83 as an example to help figure out 749+9+83=839.

4 0

2 years ago

Which function has the greatest maximum y-value?

larisa86 [58]

Answer:

g(x)

Step-by-step explanation:

y-intersect for h(x) is -11 as shown in the table, where the x value is 0

y-intersect for f(x) you find out by subbing 0 in the place of x and get the y intersect value of 2.99

y-intersect of g(x) is 3 as shown in the drawing

as seen across the three y-intersects, the value of g(x) y-intesect is the greatest

3 0

1 year ago

Together, Tim and Tom have $2.40. Tim has three times as much as Tom. How much does each have?

Phoenix [80]

X = how much Tim has
y = how much Tom has
x + y = 2.40
x = 3y
Substitute 3y for x
3y + y = 2.40
4y = 2.40
y = 0.60
Plug in y value into previous equation
x = 3(0.60)
x = 1.80
ANSWERS: Tim has $1.80 and Tom has $0.60

8 0

3 years ago

A confidence interval was used to estimate the proportion of statistics students that are female. A random sample of 72 statisti

jeyben [28]

Answer:

We need a sample of size at least 13.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence interval: (0.438, 0.642).

The proportion estimate is the halfway point of these two bounds. So

$\pi = \frac{0.438 + 0.642}{2} = 0.54$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?

We need a sample of size at least n.

n is found when M = 0.08. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.08 = 1.96\sqrt{\frac{0.54*0.46}{n}}$

$0.08\sqrt{n} = 1.96\sqrt{0.54*0.46}$

$\sqrt{n} = \frac{1.96\sqrt{0.54*0.46}}{0.08}$

$(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.54*0.46}}{0.08})^{2}$

$n = 12.21$

Rounding up

We need a sample of size at least 13.

3 0

2 years ago

Which of these is the algebraic expression for the verbal expression "ten times the difference of a number and twelve?"

fredd [130]

The answer is, A. 10(x - 12)

5 0

3 years ago