Step-by-step explanation:
x=5,y=-1
6(5)-3(-1)=30+3=33
answer G .33
Answer:
510
Step-by-step explanation:
(0.68)750
shift decimal places
510.00
refine:510
you have the ratio of natural:synthetic so;
3:4
3+4=7
357/7=51
3*51:4°51
153:204
therefore, it'd be 204 litres of synthetic oil!!
i hope this helps you!!
Answer:
<em>LCM</em> = ![8y^{4}(y+ 10)^{2}(y + 8)](https://tex.z-dn.net/?f=8y%5E%7B4%7D%28y%2B%2010%29%5E%7B2%7D%28y%20%2B%208%29)
Step-by-step explanation:
Making factors of ![8y^{6}+ 144y^{5}+ 640y^{4}](https://tex.z-dn.net/?f=8y%5E%7B6%7D%2B%20144y%5E%7B5%7D%2B%20640y%5E%7B4%7D)
Taking
common:
![\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)](https://tex.z-dn.net/?f=%5CRightarrow%208y%5E%7B4%7D%20%28y%5E%7B2%7D%2B%2018y%2B%2080%29)
Using <em>factorization</em> method:
![\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)](https://tex.z-dn.net/?f=%5CRightarrow%208y%5E%7B4%7D%20%28y%5E%7B2%7D%2B%2010y%20%2B%208y%20%2B%2080%29%5C%5C%5CRightarrow%208y%5E%7B4%7D%20%28y%20%28y%2B%2010%29%20%2B%208%28y%20%2B%2010%29%29%5C%5C%5CRightarrow%208y%5E%7B4%7D%20%28y%2B%2010%29%28y%20%2B%208%29%29%5C%5C%5CRightarrow%20%5Cunderline%7B2y%5E%7B2%7D%7D%20%5Ctimes%20%204y%5E%7B2%7D%20%5Cunderline%7B%28y%2B%2010%29%7D%28y%20%2B%208%29%29%20.....%20%281%29)
Now, Making factors of ![2y^{4} + 40y^{3} + 200y^{2}](https://tex.z-dn.net/?f=2y%5E%7B4%7D%20%2B%2040y%5E%7B3%7D%20%2B%20200y%5E%7B2%7D)
Taking
common:
![\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)](https://tex.z-dn.net/?f=%5CRightarrow%202y%5E%7B2%7D%20%28y%5E%7B2%7D%2B%2020y%2B%20100%29)
Using <em>factorization</em> method:
![\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)](https://tex.z-dn.net/?f=%5CRightarrow%202y%5E%7B2%7D%20%28y%5E%7B2%7D%2B%2010y%2B%2010y%2B%20100%29%5C%5C%5CRightarrow%202y%5E%7B2%7D%20%28y%20%28y%2B%2010%29%20%2B%2010%28y%20%2B%2010%29%29%5C%5C%5CRightarrow%20%5Cunderline%20%7B2y%5E%7B2%7D%20%28y%2B%2010%29%7D%28y%20%2B%2010%29%20%20%20%20%20%20%20%20............%20%282%29)
The underlined parts show the Highest Common Factor(HCF).
i.e. <em>HCF</em> is
.
We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:
![HCF \times LCM = p \times q](https://tex.z-dn.net/?f=HCF%20%5Ctimes%20LCM%20%3D%20p%20%5Ctimes%20q)
Using equations <em>(1)</em> and <em>(2)</em>:
![\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)](https://tex.z-dn.net/?f=%5CRightarrow%202y%5E%7B2%7D%20%28y%2B%2010%29%20%5Ctimes%20LCM%20%3D%202y%5E%7B2%7D%20%5Ctimes%20%204y%5E%7B2%7D%28y%2B%2010%29%28y%20%2B%208%29%20%5Ctimes%202y%5E%7B2%7D%20%28y%2B%2010%29%28y%20%2B%2010%29%5C%5C%5CRightarrow%20LCM%20%3D%202y%5E%7B2%7D%20%5Ctimes%20%204y%5E%7B2%7D%28y%2B%2010%29%28y%20%2B%208%29%20%5Ctimes%20%28y%20%2B%2010%29%5C%5C%5CRightarrow%20LCM%20%3D%208y%5E%7B4%7D%28y%2B%2010%29%5E%7B2%7D%28y%20%2B%208%29)
Hence, <em>LCM</em> = ![8y^{4}(y+ 10)^{2}(y + 8)](https://tex.z-dn.net/?f=8y%5E%7B4%7D%28y%2B%2010%29%5E%7B2%7D%28y%20%2B%208%29)
Formula for area of parallelogram:
A= bh
Where b is the length of base and h is the height.
Here b=2.3+4.5 = 6.8 cm
and h= 4.5 cm
Put values in formula.
A= 6.8 x 4.5
A=30.6 cm²
Answer: 30.6 cm²