All categories

3 years ago

HELP, MATH QUESTION! solve xz+y+1=z for z

1 answer:

7 0

Xz+y+1=z. given

y+1=z-xz. subtraction property of equality

y+1=z(1-x) distributive property of multiplication over addition/factoring

(1+y)/(1-x) = z division property of required, given x≠1

You might be interested in

HELP ME QUICK PLEASE THIS IS A TEST OMG

xxMikexx [17]

Answer:

It's 1/2,-2 just did the math.

3 0

3 years ago

There is something that, although it belongs to you, people always use it more than you. What is it?

Mrrafil [7]

Answer:

Your name is the answer to the riddle.

8 0

2 years ago

Darin has a rectangular vegetable garden. It is 5 yards long and 8 feet wide.

Lelu [443]

Answer:

about 15.328 yrds

Step-by-step explanation:

two sides are 5 yrds, so 5+5= 10yrds. two sides are 8 ft, 8+8=16 ft. there are .3333 yrds in 1 foot so 16*.3333 = about 5.328yrds

10+5.328 = 15.328

7 0

3 years ago

What is the line of the slope shown below

andrezito [222]

Answer:

Step-by-step explanation:

$\frac{-3-6}{2--1}=\frac{-9}{3}=3$

4 0

2 years ago

Read 2 more answers

Use the law of cosines to write an expression equivalent to b

andrezito [222]

Given:

A triangle ABC.

The given expression for b is:

$b=\sqrt{m+n-pq}$

To find:

The expression that is equivalent to b.

Solution:

According to the Law of Cosines,

$b^2=a^2+c^2-2ac\cos B$

It can be written as:

$b=\sqrt{a^2+c^2-2ac\cos B}$ ...(i)

We have,

$b=\sqrt{m+n-pq}$ ...(ii)

On comparing (i) and (ii), we get

$m=a^2$

$n=c^2$

$p=2ac$

$q=\cos B$

Therefore, the required values are $m=a^2,n=c^2,p=2ac,q=\cos B$ .

3 0

3 years ago