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nasty-shy [4]
3 years ago
5

The weight of a synthetic ball varies directly with the cube of its radius. a ball with a radius of 2 inches weighs 1.60 pounds.

find the weight of a ball of the same material with a​ 3-inch radius.
Mathematics
1 answer:
kiruha [24]3 years ago
6 0
Quick answer: 5.4 pounds for a ball 3" in radius.
Remark
You are expected to do this by calling 4/3*pi = some constant k

Givens
r = 2 inches
r1 = 3 inches

Ratio
\frac{W1}{W2} =  \frac{k r^3}{k (r1)^3}

Sub and solve 
Begin by cancelling out the ks.
\frac{W1}{W2} = \frac{r^3}{(r1)^3}

Next substitute for the 2 rs.
\frac{W1}{W2} = \frac{2^3}{3^3}

Now expand the 2 cubic amounts.
\frac{W1}{W2} = \frac{8}{27}

Conclusion Part One
The ratio of the two weights is 8/27

Part Two
Set up the ratio for 1.6 pounds to x
\frac{8}{27} = \frac{1.6}{x}

Cross multiply
8*x = 27 * 1.6  Combine the right side.
8x = 43.2    Divide by 8
x = 43.2 / 8
x = 5.4 pounds.    

If you take physics, you will do this quite frequently.
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How are y-intercepts of y=(1/3)^x and y=5(1/3)^x different?
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Remark.
The easiest way to do this question is to graph it. Start with that.
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The blue line is y = 5*(1/3)^x

Comment
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The blue line's y intercept is (0,5)

Why
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In other words, in this set of equations, the 5 makes the y intercept 5 times larger than the 1 in front of y = (1/3)^x

If you have choices, could you please list them? I may be giving you the right answer but not in the form required.

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