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nasty-shy [4]
3 years ago
5

The weight of a synthetic ball varies directly with the cube of its radius. a ball with a radius of 2 inches weighs 1.60 pounds.

find the weight of a ball of the same material with a​ 3-inch radius.
Mathematics
1 answer:
kiruha [24]3 years ago
6 0
Quick answer: 5.4 pounds for a ball 3" in radius.
Remark
You are expected to do this by calling 4/3*pi = some constant k

Givens
r = 2 inches
r1 = 3 inches

Ratio
\frac{W1}{W2} =  \frac{k r^3}{k (r1)^3}

Sub and solve 
Begin by cancelling out the ks.
\frac{W1}{W2} = \frac{r^3}{(r1)^3}

Next substitute for the 2 rs.
\frac{W1}{W2} = \frac{2^3}{3^3}

Now expand the 2 cubic amounts.
\frac{W1}{W2} = \frac{8}{27}

Conclusion Part One
The ratio of the two weights is 8/27

Part Two
Set up the ratio for 1.6 pounds to x
\frac{8}{27} = \frac{1.6}{x}

Cross multiply
8*x = 27 * 1.6  Combine the right side.
8x = 43.2    Divide by 8
x = 43.2 / 8
x = 5.4 pounds.    

If you take physics, you will do this quite frequently.
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A ball is thrown from a height of 105 feet with an initial downward velocity of 9 ft/s. The ball's height h (in feet) after t se
zloy xaker [14]

Answer:

t = 2.28 s

Step-by-step explanation:

h = 105 - 9t - 16t ^ 2

0 ft = 105 ft - 9t -16^t

To find the roots of a quadratic function we have to use the Bhaskara formula , the roots will give us the time it takes to reach zero height

ax^2 + bx + c  = 0

-16^t - 9t + 105 ft = 0 ft

a = -16    b = -9    c = 105

t1 = (-b + √ b^2 - 4ac)/2a

t2 =(-b - √ b^2 - 4ac)/2a

t1 = (9 + √(-9^2 - (4 * (-16) * 105)))/2 * (-16)

t1 = (9 + √(-81 + 6720))/ -32

t1 = (9 + √6639)/ -32

t1 = (9 + 81.84)/ -32

t1 = 90.84 / -32

t1 = -2.83 s

t2 = (9 - √(-9^2 - (4 * (-16) * 105)))/2 * (-16)

t2 = (9 - √(-81 + 6720))/ -32

t2 = (9 - √6639)/ -32

t2 = (9 - 81.84)/ -32

t2 = -72.84 / -32

t2 = 2.28 s

we have two possible values, we are only going to take the positive one, beacause we are talking about time

t2 = 2.28 s

3 0
3 years ago
If two standard six-sided dice are tossed, what is the probability that a 5 is rolled on at least one of the two dice? express y
zaharov [31]
We define the probability of a particular event occurring as:
\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have \frac{3}{36} = \frac{1}{12} probability of rolling at least one 5.
6 0
3 years ago
ZA and B are supplementary angles. If mA (x - 9)° and
Verizon [17]

The measurement of  ∠B  is 168°

Given,

In the question:

Angle A and Angle B are supplementary angles.

If mA (x - 9)° and m/B= (7x + 21)°

To find the measure of ∠B

Now, According to the question;

What are supplementary angles?

Two angles are Supplementary when they add up to 180 degrees.

Now, ∠A+∠B = 180°

So,

⇒(x - 9)˚+(7x + 21)°=180°

=> 8x +12 = 180°

=> 8x = 180° - 12

=> 8x = 168

=> x = 168/8

=> x = 21

For the measure of ∠B :

∠B  = (7x + 21)

∠B = 7 x 21 + 21

∠B  = 168°

Hence, The measurement of  ∠B  is 168°

Learn more about Supplementary angles at:

brainly.com/question/13045673

#SPJ1

5 0
1 year ago
Find the square root. <br> -√1/9
harina [27]

Answer:

-1/9

that's the answer.

BRAINLIEST PLEASE

4 0
3 years ago
I have no use for them just take them pls
masya89 [10]

Noooooo wayssssssss

I wontttttttt

8 0
2 years ago
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