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Verizon [17]
3 years ago
9

In algebra, when doing index notation, if the denominator has a higher index value than the numerator, what would simplifying th

e answer be?
For example:

c² ÷ c³
Mathematics
1 answer:
Setler [38]3 years ago
8 0
No matter what the indices are just follow the law of indices for division:

xᵃ  ÷  xᵇ  = xᵃ - ᵇ.    Most importantly the base x must be the same.

c² ÷ c³ = c² -³    = c^(-1)  =    1/c
<span> </span>
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Help! Please help me find the measure of x, the missing angle shown below -
FromTheMoon [43]

Answer:

x=21.8

Step-by-step explanation:

The angles are complementary, and add to 90 degrees. We know this because of the little square in the corner.

x+68.2=90

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x+68.2-68.2=90-68.2

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2 years ago
Read 2 more answers
X³ by a³ + a³by x³=p x³by a³- a³by ³=q eliminate x
sasho [114]

Answer:

Step-by-step explanation:

\frac{x^3}{a^3} +\frac{a^3}{x^3} =p\\\frac{x^3}{a^3} -\frac{a^3}{x^3} =q\\adding\\2\frac{x^3}{a^3} =p+q\\\frac{x^3}{a^3} =\frac{p+q}{2} \\substitute~in~first\\\frac{p+q}{2} +\frac{2}{p+q} =p\\\frac{(p+q)^2+4}{2(p+q)} =p\\(p+q)^2+4=2p(p+q)\\p^2+q^2+2pq+4-2p^2-2pq=0\\q^2-p^2+4=0\\q^2=p^2-4

6 0
2 years ago
F(x)=x^2-1 <br> G(x)=x-1 <br> find (f+g)(10).
WARRIOR [948]
<h2>Adding Functions</h2><h3>Answer:</h3>

(f +g)(10) = 108

<h3>Step-by-step explanation:</h3>

Before we can solve for (f +g)(10), we need to know how (f +g)(x) is defined.

(f +g)(x) = f(x) +g(x) \\ (f +g)(x) = (x^2 -1) +(x -1) \\ (f +g)(x) = x^2 -1 +x -1 \\ (f +g)(x) = x^2 +x -2

We can now solve for (f +g)(10):

(f +g)(10) = (10)^2 +(10) -2 \\ (f +g)(10) = 100 +10 -2 \\ (f +g)(10) = 108

6 0
2 years ago
Jack is flying his kite . He runs 100 feet away from his house and lets out 45 feet of string . The angle of elevation from the
fiasKO [112]

Answer: 125.80 ft

Step-by-step explanation:

Asuming the described situation is as shown in the figure below, we need to find the distance h between the kite and Jacks house, but first we need to find the x, y and then d.

How?

We will use trigonometry, especifically the trigonometric functions sine and cosine:

For y:

sin(65 \°)=\frac{y}{45 ft} (1)

Where y is the opposite side to the angle and 45 ft the hypotenuse.

Isolating y:

y=40.78 ft (2)

For x:

cos(65 \°)=\frac{x}{45 ft} (3)

Where x is the adjacent side to the angle.

Isolating x:

y=19.017 ft (4)

Finding d:

d=x+100 ft (5)

d=19.017 ft +100 ft

d=119.017 ft (6)

Now that we have found these values, we have to work with a bigger triangle, where the hypotenuse is the distance between the kite and Jack's house h and the sides are the values calculated in (4) and (6).

So, in this case we will use the <u>Pithagorean theorem</u>:

h^{2}=y^{2} +d^{2} (7)

Isolating h and writing with the known values:

h=\sqrt{y^{2} +d^{2}} (8)

h=\sqrt{(19.017 ft)^{2} +(119.017 ft)^{2}} (9)

h=125.80 ft This is the distance between the kite and the house

3 0
3 years ago
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