HELP AM BEING TIMED!!!!!!!!!!
2 answers:
You might be interested in
Answer: -2 ≤ D ≤ 2
Using the frequency table, it is found that:
a) 99.2% of the group of eggs were less than 24.75 mm long.
b) 0.471 = 47.1% probability that one of the eggs selected at random was at least 21.75 mm long but less than 24.75 mm long.
The frequency table gives the percentage of cuckoo bird eggs with the associated lengths.
- For example, 0.8% of eggs have lengths between 18.75 and 19.75 millimetres.
Item a:
- 0.8% of eggs were more than 24.75 mm.
Thus, 100 - 0.8 = 99.2% were less than 24.75 mm long.
Item b:
- 37.9% between 21.75 and 22.75 mm.
- 28.5% between 22.75 and 23.75 mm.
- 10.7% between 23.75 and 24.75 mm.
In total:
47.1% of the eggs are in these lengths, thus, 0.471 = 47.1% probability that one of the eggs selected at random was at least 21.75 mm long but less than 24.75 mm long.
A similar problem is given at brainly.com/question/24141790