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yanalaym [24]
3 years ago
14

Can two data sets have the same mean but different standard deviations?

Mathematics
1 answer:
agasfer [191]3 years ago
5 0

Yes they can and it depends on what the standard deviations are. The standard deviation is a measure of how close results are to the mean, a low standard deviations means the measurements are precise, so close to the mean. A high standard deviation means that measurements are more spread out.  Saying that one set is more spread out than the other.

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If you had $300 to convert to euros, would you get more than 300 euros?
Marrrta [24]

Answer:

Yes you would have more than $300 to convert to Euros.

Step-by-step explanation:

If you have $300 in america, and u convert them to euros you will have $275.43

i got this because i looked it up google :)

3 0
4 years ago
What is the range of possible sizes for side x?
Sonja [21]

Answer:

The answer is 0.5

hope this help :)

Step-by-step explanation:

7 0
3 years ago
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Novay_Z [31]
Try this:
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x=26*3=78 p.
2) if (-2) ⇒ -3*(4)=-12 ⇒ answer: (-2;-12)
if (-1) ⇒ -3*(1)=-3 ⇒ answer: (-1;-3)
if 0 ⇒ -3*0=0 ⇒ answer: (0;0)
if 1 ⇒ -3*1=-3 ⇒ answer (1;-3)
if 2 ⇒ -3*4=-12 ⇒ answer: (2;-12)
7 0
4 years ago
If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

JL = 26

KL = 19.85

\angle JKM =49

\angle JML =41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

Step-by-step explanation:

Given

MK = 30

NL = 13

\angle MKL = 41

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

NK = 15

Solving (b): JL

JL is a diagonal, and it is twice of NL.

JL = 2 * NL

JL = 2 * 13

JL = 26

Solving (c): KL

To solve for KL, we consider triangle KNL where:

\angle KNL = 90

and

KL^2 = NL^2 + NK^2

KL^2 = 13^2 + 15^2

KL^2 = 394

KL = \sqrt{394

KL = 19.85

Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

Similarly:

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

5 0
3 years ago
ou find a clue wrapped around a Toblerone bar. The base was an equilateral triangle with a side of 16 mm and the bar was 155 mm
qwelly [4]

Answer:

54 cubic inches?

Step-by-step explanation:

7 0
3 years ago
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