Ok so what y ou want to do it to max space, lie it diagonally
use pythagoren theorem
first convert the units
4'=4 feet
8''=8 inches
convert to inches
4 feet times 12=48 inches
so
pythagorea theorem is
a^2+b^2=c^2
c=hypotonuse
a and b are legs
in a right triangle
8 and 48 are the legs
fidn hypotonuse
8^2+48^2=c^2
64+2304=c^2
2368=c^2
8√37=c
aprox
48.66=c
4 feet amd 0.66 inches
The trick here is to notice that all 3 terms can be div. by 2:
2(x^2 + x - 12)
Note that -12 factors into -3 * 4 or -4 * 3. Thus,
x^2 + x - 12 = (x-4)(x+3), and so <span>2x2 + 2x − 24 = 2(x-4)(x+3).</span>
Answer:
No
Step-by-step explanation:
For shapes to be similar, their ratios of length-to-length and width-to-width must be the same. When you divide the larger length by the smaller length and the larger width by the smaller width, do you get the same number? No, so these rectangles are not similar.
The hypotenuse is 20.59. 10^2+18^2=C^2
To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is ![\frac{d}{dx} [x^{n} ] =nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bx%5E%7Bn%7D%20%5D%20%3Dnx%5E%7Bn-1%7D)
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) = 
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
