All categories

3 years ago

If ORBIT is coded BEOVG, then how is PLANET coded? /

Mathematics

1 answer:

arlik [135]3 years ago

4 0

Answer:

1. CYNARG

Step-by-step explanation:

This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:

$C = (P + o) \text{mod} 26$

In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.

Finding the offset:

O is coded B

O is the 15th letter in the alphabet, so $P = 15$ .

B is the 2nd letter in the alphabet, so $C = 2$

$C = (P + o) \text{mod} 26$

$2 = (15 + o) \text{mod} 26$

$|o = |2-15| \text{mod} 26$

$o = 13$

$C = (P + 13) \text{mod} 26$

PLANET:

P is the 16th letter in the alphabet.

$C = (16 + 13) \text{mod} 26 = 3$

So P is coded C.

L is the 12th letter in the alphabet:

$C = (12 + 13) \text{mod} 26 = 25$

L is coded Y(25th letter in the alphabet)

A is the 1st letter in the alphabet

$C = (1 + 13) \text{mod} 26 = 14$

A is coded N

N is the 14th letter in the alphabet

$C = (14 + 13) \text{mod} 26 = 1$

N is coded A

E is the 5th letter in the alphabet

$C = (5 + 13) \text{mod} 26 = 18$

E is coded R

So the correct answer is:

1. CYNARG

You might be interested in

Let f(x)=x+2 and g(x)=2x+1 .

gogolik [260]

Step-by-step explanation:

Given g(x) = x+2 and f(x) = $2^x+1$

If f(x) = g(x)

⇔ $2^x+1$ = x+2

⇔ $2^x= x +1$

Only x= 1 and x=0 will be satisfy the above equation.

If x= 1, it gives and x=0 gives

$2^1= 1+1$ $2^0=0+1$

⇔2=2 ⇔1=1

7 0

3 years ago

Read 2 more answers

Aaron bought a set of plastic ice cubes with a mixture of water and air inside.

LekaFEV [45]

Answer:

Volume of water and air is 3,000 mm³

Step-by-step explanation:

Given:

Length of base = 15 mm

Width of base = 20 mm

Height of figure = 30 mm

Find:

Volume of water and air is inside each of the plastic ice cubes.

Computation:

Height of each rectangular pyramid = Height of figure / 2

Height of each rectangular pyramid = 30 / 2

Height of each rectangular pyramid = 15 mm

Volume of each rectangular pyramid = lbh / 3

Volume of each rectangular pyramid = [15 × 20 × 15] / 3

Volume of each rectangular pyramid = [4,500] / 3

Volume of each rectangular pyramid = 1,500 mm³

Volume of water and air is inside each of the plastic ice cubes = 2 × Volume of each rectangular pyramid

Volume of water and air is inside each of the plastic ice cubes = 2 × 1,500

Volume of water and air is inside each of the plastic ice cubes = 3,000 mm³

6 0

3 years ago

Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane

storchak [24]

Answer:

$f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)$

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

$f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)$

Note that