Your method is completely correct. The first term will be 6 and each subsequent term can be obtained by adding 6 to the previous one, meaning the common difference is 6. The number of terms is given by the highest number that is divisible by 6 and dividing it by 6; that is 996/6 = 166
Then we simply apply the formula for arithmetic sequence sum:
S = n/2 [2a₁ + (n - 1)d]
S = 166/2 [ 2(6) + (166 - 1)6]
S = 83,166
-17 as negative values become less as its debt.
<span>8x² - x + x² + 4x - 9x² = 18
3x = 18 | 8x</span>² + x² - 9x² = 0<span>
x = 6 | divide by 3
Answer: x = 6</span>
Answer:
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Step-by-step explanation: