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ch4aika [34]
3 years ago
9

I KNOW IT IT LONG BUT PLEASE HELP ME PLEASE

Mathematics
2 answers:
vovangra [49]3 years ago
6 0

Answer:

8 points only for that of a long question

Step-by-step explanation:

masha68 [24]3 years ago
5 0

Answer:

ey man how are u

Step-by-step explanation:

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Suppose an airline policy states that all baggage must be box shaped with a sum of​ length, width, and height not exceeding 114
NISA [10]

Answer:

Step-by-step explanation:

Represent the length of one side of the base be s and the height by h.  Then the volume of the box is V = s^2*h; this is to be maximized.

The constraints are as follows:  2s + h = 114 in.  Solving for h, we get 114 - 2s = h.

Substituting 114 - 2s for h in the volume formula, we obtain:

V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)

This is to be maximized.  To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:

dV

----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2

ds

Simplifying this, we get dV/ds = -4s^2 + 114s = 0.  Then either s = 28.5 or s = 0.

Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in

and the volume is V = s^2(h) = 46,298.25 in^3

7 0
3 years ago
Whats the answer to 30 less than 10
Deffense [45]

We are looking for a new number which is 30 less than 10. We will get the new number by subtracting 30 from 10. We write it down as: 10-30=-20


And finally the solution for: What number is 30 less than 10? is -20 

Hope this helps!!
6 0
3 years ago
Read 2 more answers
What is the x intercepts of the mid point f(x)=(x-2)(x-4)
BigorU [14]
F(x)= -2x+6 i think so
6 0
3 years ago
A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75 and a sample variance of 25
GREYUIT [131]

Answer:

The upper limit of a 95% confidence interval for the population mean would equal 83.805.

Step-by-step explanation:

The standard deviation is the square root of the variance. Since the variance is 25, the sample's standard deviation is 5.

We have the sample standard deviation, not the population, so we use the t-distribution to solve this question.

T interval:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 15 - 1 = 14

Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 0.95(t_{95}). So we have T = 1.761

The margin of error is:

M = T*s = 1.761*5 = 8.805.

The upper end of the interval is the sample mean added to M. So it is 75 + 8.805 = 83.805.

The upper limit of a 95% confidence interval for the population mean would equal 83.805.

4 0
3 years ago
Henry wants to earn more than $68 trimming trees. He charges $6 per hour and pays $4 in equipment fees. What are the possible nu
nexus9112 [7]
68>6t+4 when ever the number is per something(the 6) you put the variable with it and 4 is the constant

t>16
5 0
3 years ago
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