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3 years ago

I KNOW IT IT LONG BUT PLEASE HELP ME PLEASE

Mathematics

2 answers:

vovangra [49]3 years ago

6 0

Answer:

8 points only for that of a long question

Step-by-step explanation:

masha68 [24]3 years ago

5 0

Answer:

ey man how are u

Step-by-step explanation:

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. Simplify an expression for the area of the rectangle shown above

mel-nik [20]

8x+3x5=66 there you go

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2 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

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2 years ago

Solve x2-4x-7=0 by completing the square

aleksklad [387]

HEY mate here is pratyush from India for your help...

the answer is with the attachment

hope it helps you..

8 0

2 years ago

Read 2 more answers

Please help answer ASAP

sweet-ann [11.9K]

0.77875...

which, I'm assuming, they want you to round to the nearest hundredth? So, .78?...

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2 years ago

Read 2 more answers

I NEED HELP please

Daniel [21]

Answer:

1. =2

2. times 2

3. b.

Step-by-step explanation:

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2 years ago