Answer:
H0 : p = 0.75 against H1: p > 0.75 One tailed test.
Step-by-step explanation:
We state our null and alternative hypotheses as
H0 : p = 0.75 against H1: p > 0.75 One tailed test.
In this case H0 is not defined as p≤ 0.75 because the acceptance and rejection regions cannot be set up. Therefore we take the exact value of H0 : p= 0.75.
The claim is that the probability of the workers getting their job through the internet is greater than 75% or 0.75.
As H0 is supposed to be less than we choose H1 to be greater than equality.
D 288 1/3 = 96/288 3/4 = 216/288 5/32 = 45/288 8/9 = 256/288
1/3 times 96 3/4 times 72 5/32 times 9 8/9 times 32
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Answer:
if the stone makes 150 revolution per minute, the tension force of the string on the stone is
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Answer:
10/12 or simplified its 5/6
Step-by-step explanation:
3+7 = 10
you keep the 12
10÷2 = 5
12÷2=6
common denominator
