Why is 6/11=x/33 not a proportion

Mathematics

1 answer:

sertanlavr [38]3 years ago

6 0

6/11=x/33 is not a proportion because they aren't equal to each other.

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Solve the equation 6/5y-10=-4 X=

defon

6/5y-10=-4

move -10 to the other side

sign changes from -10 to 10

6/5y-10+10= -4+10

6/5y= 6

Mutiply by 5/6 for both sides

6/5(5/6)y=6(5/6)

Cross out 6/5 and 5/6 , divide by 5 and 6 then becomes y

Cross out 5 and 6 on the right side

x= 5

Answer : x= 5

3 0

3 years ago

Will Mark Brainliest ! Please Answer Quickly!!!!!!!!!!!! 18+pts!!

arlik [135]

I'm pretty sure the answers are correct because on the question it says for every 8ft is one inch

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3 years ago

leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. the triangular base has a

Georgia [21]

The answer is $x = \frac{-7+ \sqrt{193} }{4}$ .

There is very similar question on Brainly, in which dimensions of the living room are given (20 feet, 30 feet).
So, knowing this, we first need to calculate how much 6% of the living room is.
The area of the living room is 600 square feet, since it is rectangle-shaped:
P = a * b = 200 feet * 30 feet = 600 square feet.

6% of 600 square feet is 36 square feet:
600 square feet : 100% = A : 6%
A = 600 * 6 / 100 = 36 square feet

The area of the triangular-based cabinet (A) is $A = \frac{a*h}{2}$ , where a is the base, and h is the height of the triangle.
It is given:
A = 36
a = 2x + 3
h = 3x + 6

Now, let's implement this to the formula $A = \frac{a*h}{2}$ :
$36 = \frac{(2x+3)(3x+6)}{2}$
⇒ $36*2=6 x^{2} +12x+9x+18$
$72=6 x^{2} +21x+18$

Let's both sides divide by 3:
$24=2 x^{2} +7x+6$
⇒ $2 x^{2} +7x-18=0$

This is the quadratic formula ( $a x^{2} +bx+c=0$ ) for which
$x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}$ or
 $x = \frac{-b-\sqrt{b^{2} -4ac} }{2a}$ .
We will use only $x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}$ , because the length cannot have negative value.

From the equation $2 x^{2} +7x-18=0$ , we know that
a = 2
b = 7
c = -18

Thus, $x = \frac{-7+ \sqrt{193} }{4}$ :
 $x= \frac{-b+ \sqrt{ b^{2} -4ac} }{2a} = \frac{-7+ \sqrt{ (7)^{2} -4*2*(-18)} }{2*2} = \frac{-7+ \sqrt{49+144} }{4} = \frac{-7+ \sqrt{193} }{4}$

4 0

3 years ago

Factorise 3ab²+15a²b³+21a³b²

evablogger [386]

Given:

The expression is

$3ab^2+15a^2b^3+21a^3b^2$