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blsea [12.9K]
3 years ago
7

Why is 6/11=x/33 not a proportion

Mathematics
1 answer:
sertanlavr [38]3 years ago
6 0

6/11=x/33 is not a proportion because they aren't equal to each other.

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A bouqet had 10 flower and sold it for 90$ which is the rate of $_ per flower
lana [24]

Answer:

$9 per flower

Step-by-step explanation:

divide cost ($90) by the number of items (10 flowers)

6 0
3 years ago
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Prove that XR is equivalent to YP by using the terms in geometry, its just proofs
Sophie [7]
PQRS is a parallelogram                   Given
SR=PQ                                               property of parallelogram
m∠S=m∠Q                                         property of parallelogram
SP=QR                                               property of parallelogram
XP=RY                                               given
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XR=YP                                              CPCTC (corresponding parts of                                                                          congruent triangles are congruent)

3 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
Any suggestions or answers
OLEGan [10]
2nd answer.

any pts in the shaded region satisfies your simultaneous equation.
5 0
3 years ago
I need help due in 10 minutes ah!
dimaraw [331]

Answer:

30

Step-by-step explanation:

If CUB is 78 and that’s the full angle just to 48 minus 78 and you get your answer.

7 0
2 years ago
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