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Blababa [14]
3 years ago
13

Pleaseee help I need fast and right

Mathematics
1 answer:
Alinara [238K]3 years ago
8 0

Answer: e. x≠2             f. x≥-1/2

Step-by-step explanation:

Domain is basically the x value of a function.

----------------------------------------------------------------

Question e.

g(x)=5/(2-x)

First, keep in mind, the denominator of a fraction can not be zero or else it will be undefined.

Since x is in the denominator: 2-x≠0

2-x≠0

<h2>    x≠2 Yes, this is the domain</h2>

----------------------------------------------------------------

Question f

h(x)=√(2x+1)

For a standard square root, the value inside can't b negative

So 2x+1≥0

        2x≥-1

<h2>           x≥-1/2 Yes, this is the domain</h2><h2 />

Hope this helps!! :)

Please let me know if you have any question

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\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

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<u>Calculus</u>

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Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

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  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
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