All categories

3 years ago

Pleaseee help I need fast and right

Mathematics

1 answer:

Alinara [238K]3 years ago

8 0

Answer: e. x≠2 f. x≥-1/2

Step-by-step explanation:

Domain is basically the x value of a function.

----------------------------------------------------------------

Question e.

g(x)=5/(2-x)

First, keep in mind, the denominator of a fraction can not be zero or else it will be undefined.

Since x is in the denominator: 2-x≠0

2-x≠0

<h2> x≠2 Yes, this is the domain</h2>

----------------------------------------------------------------

Question f

h(x)=√(2x+1)

For a standard square root, the value inside can't b negative

So 2x+1≥0

2x≥-1

<h2> x≥-1/2 Yes, this is the domain</h2><h2 />

Hope this helps!! :)

Please let me know if you have any question

You might be interested in

Can someone please help me ASAP

Natasha2012 [34]

7^2 +6 ^2= 85
Square root of 85 = 9.219544457

Answer : 9.2

3 0

3 years ago

Read 2 more answers

Please Help Me ASAP I Need <br> This For My grade

mel-nik [20]

Answer:

$\huge slope \: of \: the \: graph = \tan( \alpha ) = \frac{perpendicular}{base} = \frac{(value\:of\: y-axis)}{(value\:of\:x-axis)} = \frac{1}{ - 1} = - 1$

<h2>-1 is the right answer.</h2>

5 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

Expanding/Factoring

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

<u>Step 2: Differentiate</u>

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$