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Blababa [14]
3 years ago
13

Pleaseee help I need fast and right

Mathematics
1 answer:
Alinara [238K]3 years ago
8 0

Answer: e. x≠2             f. x≥-1/2

Step-by-step explanation:

Domain is basically the x value of a function.

----------------------------------------------------------------

Question e.

g(x)=5/(2-x)

First, keep in mind, the denominator of a fraction can not be zero or else it will be undefined.

Since x is in the denominator: 2-x≠0

2-x≠0

<h2>    x≠2 Yes, this is the domain</h2>

----------------------------------------------------------------

Question f

h(x)=√(2x+1)

For a standard square root, the value inside can't b negative

So 2x+1≥0

        2x≥-1

<h2>           x≥-1/2 Yes, this is the domain</h2><h2 />

Hope this helps!! :)

Please let me know if you have any question

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Select true or false <br><br> (1/64)-5/6= 32
Otrada [13]

(1/64)-5/6 = 32

To subtract fractions they must have common denominators, so find the least common multiple of 64 and 6 (the denominators of the fractions).

The least common multiple of the two fractions' denominators is 192. To get 64 to 192, you would multiply 64 by 3 times. If you're multiplying 64 by 3, you also multiply the numerator by 3.

1/64 * 3/3 = 3/192

Now to get 6 to 192, you would multiply 6 by 32. If you're multiplying 6 by 32 then you will also multiply the numerator (5) by 32.

5/6 * 32/32 = 160/192

Subtract the fractions now that they have common denominators. You'll only need to subtract the numerators.

3/192-160/192 = -157/192

You cannot simplify this any farther, so that will be your true answer. -157/192 is NOT equal to 32, so this means the answer is false.

Answer is:

false

6 0
3 years ago
Use mental math to find the equations that are true. Select all that apply.
Alex777 [14]

Answer:

A, C, D, E

Step-by-step explanation:

7 0
3 years ago
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Determine the quadrant when the terminal side of the angle lies according to the following conditions: sin (t) &gt; 0, cos (t) &
grin007 [14]
Check the problem again!Cosecant (csc) is the reciprocal of sine (sin) so they are always either both positive or both negative. Perhaps it should be sine < 0 and cosine > 0? In that case, sine is less than zero in quadrants 3 and 4, and cosine is greater than zero in quadrants 1 and 4, so this angle can only lie in quadrant 4. On the unit circle, remember that cosine is the x-coordinate of the terminal side of the angle and sine is the y-coordinate.  Quadrant 1 is that where both sine and cosine are greater than zero.  The rest of them are numbered consecutively going counter-clockwise; so quadrant 2 has cos < 0 and sin > 0, quadrant 3 has cos < 0 and sin < 0, and quadrant 4 has cos > 0 and sin < 0
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4 years ago
Two sides of a triangle measure 17 inches and 20 inches. Which CANNOT be the length of the remainig side?
yaroslaw [1]
<h3>Answer:  37</h3>

========================================================

Work Shown:

We have a triangle with sides a,b,c such that

  • a = 17
  • b = 20
  • c = unknown

The third side c can be represented by this inequality

b-a < c < b+a

which is a modified form of the triangle inequality theorem.

Plug in the given values to get

b-a < c < b+a

20-17 < c < 20+17

3 < c < 37

The third side length is between 3 and 37; it cannot equal 3, and it cannot equal 37. So we exclude both endpoints.

Of the answer choices, the values {7,20, 12} are in the range 3 < c < 37.

The value c = 37 is not in the range 3 < c < 37 because we can't have the third side equal to either endpoint. Otherwise, we get a straight line instead of a triangle forming.

So that's why 37 is the only possible answer here.

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3 years ago
4T + 2(2T - 4) = 7T + 3(9 + 2) + 1T
Kruka [31]
0=41
(need 20 characters dont mind this)
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